The angle between a principal plane and plane of maximum shear is
45°
The question asks for the angle between a principal plane and a plane of maximum shear.
In stress analysis, a principal plane is a plane within a material under stress where the shear stress is zero. Only normal stress (tensile or compressive) acts on these planes. For a 2D stress state, there are typically two principal planes, corresponding to the maximum and minimum normal stresses, often denoted as $\sigma_1$ and $\sigma_2$. These planes are perpendicular to each other.
Planes of maximum shear are planes where the shear stress acting on them reaches its maximum possible value for a given stress state. On these planes, the normal stress is intermediate between the principal stresses.
The relationship between the directions of principal planes and planes of maximum shear can be visualized using Mohr's circle:
Therefore, the plane of maximum shear is oriented at an angle of $45^\circ$ with respect to the principal planes.
The angle between a principal plane and a plane of maximum shear is $45^\circ$.
A shaft subjected to torsion experiences a pure shear stress τ on the surface. The maximum principal stress on the surface which is at 45° to the axis will have a value
A solid circular shaft of diameter 100 mm is subjected to an axial stress of 50 MPa. It is further subjected to a torque of 10 kNm. The maximum principal stress experienced on the shaft is closest to
The diagonal elements of a 3D matrix containing normal stresses and shear stresses are 50, 60 and 80. Find the first stress invariant of the matrix.
The relation between maximum shear stress (τm) and maximum normal stress (σm ) in an axially loaded rectangular bar is:
Analytical and graphical methods are used for finding the ________ on an oblique section.