The question concerns the chemical equilibrium of acetic acid (CH3COOH) in solution. The dissociation reaction is represented as:
$$ \text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+ $$
This equilibrium involves a weak acid, acetic acid, partially dissociating into its conjugate base, the acetate ion (CH3COO-), and hydrogen ions (H+).
To determine the effect of adding H+ ions, we apply Le Chatelier's principle. This principle states that if a change (like adding or removing a substance, changing temperature, or changing pressure) is applied to a system at equilibrium, the system will shift in a direction that counteracts the applied change.
In this specific case:
The reaction consumes H+ ions when it proceeds in the reverse direction (from right to left). Therefore, adding H+ ions will cause the equilibrium to shift towards the reactants:
$$ \text{CH}_3\text{COO}^- + \text{H}^+ \rightarrow \text{CH}_3\text{COOH} $$
This shift means that the concentration of undissociated acetic acid (CH3COOH) will increase, while the concentrations of acetate ions (CH3COO-) might decrease (as they react with the added H+) or increase less than they would have without the added H$^+$, depending on the specific concentrations and the extent of the shift.
The equilibrium position moves to the left.
What is the pH of a solution prepared by dissolving $0.0025$ moles of $HNO_3$ in $250\,mL$ of water?
Which species acts as acid like behaviour in the following reaction?
\(HPO_4^{2-}+NH_4^{1+}\rightarrow H_2PO_4^{1-}+NH_3\)
Aqueous solution of CH 3COONa is:
pH of a neutral solution is ___________.
For the reaction N 2(g) + 3H 2(g) \(\rightleftharpoons\) 2NH 3(g) ΔH = -ve :