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Question

The addition of H$^+$ ions to the equilibrium CH$_3$COOH $\rightleftharpoons$ CH$_3$COO$^-$ + H$^+$ will:

The correct answer is
Shift the equilibrium left

Understanding the Acetic Acid Equilibrium

The question concerns the chemical equilibrium of acetic acid (CH3COOH) in solution. The dissociation reaction is represented as:

$$ \text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+ $$

This equilibrium involves a weak acid, acetic acid, partially dissociating into its conjugate base, the acetate ion (CH3COO-), and hydrogen ions (H+).

Applying Le Chatelier's Principle

To determine the effect of adding H+ ions, we apply Le Chatelier's principle. This principle states that if a change (like adding or removing a substance, changing temperature, or changing pressure) is applied to a system at equilibrium, the system will shift in a direction that counteracts the applied change.

In this specific case:

  • Change Applied: Addition of H+ ions.
  • System's Reaction: H+ is a product in the equilibrium reaction. Adding more of a product disturbs the equilibrium.
  • Counteraction: To counteract the increase in [H+], the system will try to consume the excess H+ ions.

Effect on Equilibrium Position

The reaction consumes H+ ions when it proceeds in the reverse direction (from right to left). Therefore, adding H+ ions will cause the equilibrium to shift towards the reactants:

$$ \text{CH}_3\text{COO}^- + \text{H}^+ \rightarrow \text{CH}_3\text{COOH} $$

This shift means that the concentration of undissociated acetic acid (CH3COOH) will increase, while the concentrations of acetate ions (CH3COO-) might decrease (as they react with the added H+) or increase less than they would have without the added H$^+$, depending on the specific concentrations and the extent of the shift.

The equilibrium position moves to the left.

Analyzing the Options

  • 1. Lead to no change: Incorrect. Adding a product affects the equilibrium position.
  • 2. Stop the reaction: Incorrect. Equilibrium shifts, reactions don't necessarily stop completely.
  • 3. Shift the equilibrium right: Incorrect. Shifting right would mean producing more products (H+ and CH3COO-), which is the opposite of what happens when H+ is added.
  • 4. Shift the equilibrium left: Correct. Adding H+ drives the reaction in reverse, consuming products and forming reactants, thus shifting the equilibrium to the left.
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Important Questions from Equilibrium

  1. What is the pH of a solution prepared by dissolving $0.0025$ moles of $HNO_3$ in $250\,mL$ of water?

  2. Which species acts as acid like behaviour in the following reaction?

    \(HPO_4^{2-}+NH_4^{1+}\rightarrow H_2PO_4^{1-}+NH_3\)

  3. Aqueous solution of CH 3COONa is:

  4. pH of a neutral solution is ___________.

  5. For the reaction N 2(g) + 3H 2(g) \(\rightleftharpoons\)  2NH 3(g) ΔH = -ve : 

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