$v_a(t) = 0.8 \sin(\omega t) \text{ V}$
$v_b(t) = 0.8 \sin\left(\omega t - \frac{2\pi}{3}\right) \text{ V}$
$v_c(t) = 0.8 \sin\left(\omega t + \frac{2\pi}{3}\right) \text{ V}$
where $\omega = 2\pi \times 40 \text{ rad/s}$ is the fundamental frequency. The modulating waveforms are compared with a $10 \text{ kHz}$ triangular carrier whose magnitude varies between $+1$ and $-1$. The VSI has a DC link voltage of $600 \text{ V}$ and feeds a star connected motor. The per phase fundamental RMS motor voltage in volts is closest to
Identify the given parameters for the 3-phase Voltage Source Inverter (VSI) using Sinusoidal Pulse Width Modulation (SPWM).
The modulation index ($m_a$) is the ratio of the modulating signal amplitude to the carrier signal amplitude.
$m_a = \frac{A_m}{A_c} = \frac{0.8}{1} = 0.8$
For a VSI operating in the linear region with SPWM, the peak fundamental phase voltage ($V_{ph, \text{peak}}$) is calculated as:
$V_{ph, \text{peak}} = m_a \times \frac{V_{dc}}{2}$
Substituting the known values:
$V_{ph, \text{peak}} = 0.8 \times \frac{600 \text{ V}}{2} = 0.8 \times 300 \text{ V} = 240 \text{ V}$
The fundamental RMS phase voltage ($V_{ph, \text{RMS}}$) is obtained by dividing the peak voltage by $\sqrt{2}$.
$V_{ph, \text{RMS}} = \frac{V_{ph, \text{peak}}}{\sqrt{2}} = \frac{240 \text{ V}}{\sqrt{2}}$
$V_{ph, \text{RMS}} \approx \frac{240}{1.41421356} \text{ V} \approx 169.71 \text{ V}$
The per phase fundamental RMS motor voltage is closest to 169.71 V.
Output voltage wave shape of a basic series inverter is
The output of SMPS is ______.
Which one of the following controls reduce the size of the transformer in a switch mode AC power supply?
The rms value of load phase voltage is
If the dc bus voltage Vd = 300 V, the power consumed by 3-phase load is