Let's break down this age problem step-by-step.
We are given:
Substitute the expressions for Tejasvi's and Meena's ages 4 years ago into the ratio equation:
$ \frac{x - 4}{2x - 4} = \frac{1}{3} $
Cross-multiply to solve for $x$:
$ 3(x - 4) = 1(2x - 4) $
$ 3x - 12 = 2x - 4 $
Rearrange the terms to isolate $x$:
$ 3x - 2x = 12 - 4 $
$ x = 8 $
So, the current age of Tejasvi and Trishana is 8 years.
We need to find Trishana's age 4 years from now.
Therefore, Trishana will be 12 years old 4 years from now.
The average age of a husband and his wife was 20 years at the time of their marriage. After 6 years, they have a 2 -year old child. Find the present average age of the family.
The ratio of the ages of A, B and C, 5 years ago, was 4 : 5 : 7. The sum of their present ages is 135 years. What will be the sum of the ages (in years) of B and C, 3 years from now?
The ratio of the present age of Mahesh and Ajay is 3 : 2 respectively. After 8 years. Ratio of their age will be 11: 8. What will be the present age of Mahesh’s son if his age is half of the present age of Ajay?
In a school, the average age of boys and girls together is 16.8 years, the average age of boys is 15.4 years, and the average age of girls is 18.2 years. The ratio of number of boys to girls in the school is:
The difference between age of Sunita and Sheela is 12 years. If 9 years ago, elder's age was 4 times of younger's age, then what are their present age?
A. 11 and 23
B. 15 and 27
C. 13 and 25
D. 23 and 35