Let's break down this age problem step-by-step.
We are given:
Substitute the expressions for Tejasvi's and Meena's ages 4 years ago into the ratio equation:
$ \frac{x - 4}{2x - 4} = \frac{1}{3} $
Cross-multiply to solve for $x$:
$ 3(x - 4) = 1(2x - 4) $
$ 3x - 12 = 2x - 4 $
Rearrange the terms to isolate $x$:
$ 3x - 2x = 12 - 4 $
$ x = 8 $
So, the current age of Tejasvi and Trishana is 8 years.
We need to find Trishana's age 4 years from now.
Therefore, Trishana will be 12 years old 4 years from now.
The ratio of present ages of Neelam and Rajni is 6 : 7. After four years, their ages will be in the ratio of 8 : 9. What is the present age of Rajni?
Five years ago the age of the son was one third of that of his mother at that time. If the sum of their present ages is 70 years, then find the present age of the mother.
Jaya is 36 years old and her son Bharat is 11 years old. In how many years will Jaya be twice as Bharat's age?
Five years ago, father's age was 5 times that of his son and after 3 years he will be 3 times as old as his son. Find the present age of son.
The ratio of a father's age to his son's age is 3 ∶ 2 The product of the numbers representing their age is 486. The ratio of their ages after 5 years will be: