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Question

Suresh walks 10 km North, then 6 km East, then 10 km South, then 2 km West. What is the shortest distance and in which direction is he from his starting point ?

The correct answer is
4 km East

Movement Analysis

To find Suresh's final position relative to his starting point, we analyze his movements along the North-South and East-West axes.

  • North-South Travel: Suresh walks 10 km North (+10 km) and then 10 km South (-10 km). The net displacement in the North-South direction is $10 \text{ km} - 10 \text{ km} = 0 \text{ km}$.
  • East-West Travel: Suresh walks 6 km East (+6 km) and then 2 km West (-2 km). The net displacement in the East-West direction is $6 \text{ km} - 2 \text{ km} = 4 \text{ km}$ East.

Final Displacement Calculation

Combining the net displacements:

  • Net North-South displacement = $0$ km.
  • Net East-West displacement = $4$ km East.

Suresh's final position is effectively 4 km East of his starting point. This net displacement represents the shortest distance and the direction from the start.

Result

The shortest distance from the starting point is 4 km, and the direction is East.

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Important Questions from Direction and Distance

  1. What is the direction of U with respect to P?

  2. What is the shortest distance between R and T?

  3. If a person walks 3m towards the North from point V, takes a right turn and walks for another 15m, which of the following points would he reach?

  4. In which direction is Amit facing at point F?

  5. What is the distance between the starting point and the end point?

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