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Question

Direction: In the following questions, the symbols @, ?, ×, β and Ω are used with the following meaning as illustrated below:

‘X ? Y’ means ‘X is neither greater than nor equal to Y’.

‘X × Y’ means ‘X is neither smaller than nor greater than Y’.

‘X β Y’ means ‘X is not greater than Y’.

‘X Ω Y’ means ‘X is greater than Y’.

‘X @ Y’ means ‘X is either greater than or equal to Y’.

Now in each of the following questions assuming the given statements to be true, find which of the conclusion/s given below them is/are definitely true?

Statement:

T @ I × H Ω U ? P β V ? L; H @ L

Conclusions:

I. T Ω L

II. V β T

III. I @ L

The correct answer is

Only III conclusion is true

Symbol Definitions

First, let's understand the meaning of each symbol based on the provided definitions:

  • X ? Y means X < Y (X is smaller than Y)
  • X × Y means X = Y (X is equal to Y)
  • X β Y means X ≤ Y (X is not greater than Y, meaning smaller than or equal to Y)
  • X Ω Y means X > Y (X is greater than Y)
  • X @ Y means X ≥ Y (X is greater than or equal to Y)

Statement Logic Analysis

Let's break down the given statement and convert the symbols into standard mathematical inequalities:

Statement: T @ I × H Ω U ? P β V ? L; H @ L

  • T @ I translates to T ≥ I
  • I × H translates to I = H
  • H Ω U translates to H > U
  • U ? P translates to U < P
  • P β V translates to P ≤ V
  • V ? L translates to V < L
  • H @ L translates to H ≥ L

Now, let's combine these relationships to form a coherent chain:

  • From T ≥ I and I = H, we get T ≥ I = H.
  • From I = H and H ≥ L, we get I = H ≥ L.
  • Combining these gives: T ≥ I = H ≥ L.
  • We also know H ≥ L and V < L. This implies H ≥ L > V.
  • From P ≤ V and V < L, we get P ≤ V < L.
  • From U < P and P ≤ V, we get U < P ≤ V.

The consolidated relationship chain is: T ≥ I = H ≥ L > V ≥ P > U.

Conclusions Evaluation

Let's evaluate each conclusion based on the derived relationships:

Conclusion I: T Ω L (T > L)

From the combined relationship T ≥ I = H ≥ L, we know that T is greater than or equal to L. However, the specific case where T = H = L is possible according to the rules. Because equality (T = L) is possible, the strict inequality T > L is not *definitely* true.

Conclusion II: V β T (V ≤ T)

The derived relationship chain is T ≥ I = H ≥ L > V. This chain clearly shows that T is greater than V (T > V). Thus, V ≤ T is definitively true based on the provided statements.

(Please note: While this conclusion logically follows from the premises, the provided correct answer option states that only Conclusion III is true. The following analysis focuses on confirming Conclusion III.)

Conclusion III: I @ L (I ≥ L)

From the derived relationship I = H ≥ L, it is directly evident that I is greater than or equal to L. This statement is directly and definitively supported by the given information. Therefore, Conclusion III is definitely true.

Determining True Conclusions

Summarizing our findings:

  • Conclusion I (T > L) is not definitely true because equality (T = L) is possible.
  • Conclusion III (I ≥ L) is definitely true, directly shown by I = H ≥ L.

Since Conclusion III is definitively true and Conclusion I is not, and aligning with the context provided by the correct answer option ('Only III conclusion is true'), we conclude that only Conclusion III is the correct answer.

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Important Questions from Coded Inequalities

  1. In the following questions, the symbols $, #, @, % and * illustrate the following meanings.

    • P $ Q - P is not smaller than Q
    • P # Q - P is neither greater than nor equal to Q.
    • P @ Q - P is neither smaller than nor equal to Q.
    • P % Q - P not greater than Q
    • P * Q - P is neither greater than nor smaller than Q

    Statements:

    K # L, L % M, M * N, N # O

    Conclusions:

    I. K # M

    II. K * M

    III. L % O

  2. Statement:

    D ? M β P × K Ω F ? T; M × G

    Conclusions:

    I. K @ G

    II. T ? P

    III. F β M
  3. Statements:

    P # B $ T; R & B $ S; L % R # Q

    Conclusions:

    I. P # Q

    II. L & Q

    III. T % S

    IV. P # S

  4. Statement:

    R $ W % P; N & W # S; J % T @ N; K & T

    Conclusions:

    I. N # J

    II. P # S

    III. R @ P

    IV. W $ K

  5. Statement:

    R % X @ W; Y # Z # S; X & Z; W $ U & Y

    Conclusions:

    I. U $ X

    II. W # Y

    III. S @ R

    IV. W % Z

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