Starting from the same point at the same time, A and B run on a 3600 m circular track with speeds of 4 m/s and 6 m/s, clockwise. After A completes the first round on the track, she reverses direction and runs anticlockwise. After how many seconds of starting the run would they cross for the first time?
1080
This problem involves two runners, A and B, on a circular track. They start at the same point and time, but A changes direction after completing the first round. We need to find the exact time from the start when they meet for the first time.
Here are the key details:
First, let's figure out how long it takes A to complete one full round of the track, as this is when A changes direction.
Time = Distance / Speed
\( \text{Time for A's first round} = \frac{\text{Track length}}{\text{A's speed}} \)
\( \text{Time} = \frac{3600 \text{ m}}{4 \text{ m/s}} = 900 \text{ seconds} \)
So, at \(t = 900\) seconds from the start, A is back at the starting point.
At \(t = 900\) seconds:
Distance covered by B = B's speed \(\times\) Time
\( \text{Distance covered by B} = 6 \text{ m/s} \times 900 \text{ s} = 5400 \text{ m} \)
To find B's position on the circular track, we find the remainder after dividing the distance covered by the track length:
\( 5400 \text{ m} = 1 \times 3600 \text{ m} + 1800 \text{ m} \)
This means B has completed 1 full round and is 1800 m clockwise from the starting point at \(t = 900\) seconds.
At \(t = 900\) seconds:
Now, A is moving anticlockwise from the starting point, and B is moving clockwise from a point 1800 m away clockwise. They are effectively moving towards each other along the track.
The distance between them along the track at this moment is 1800 m (the shorter arc between the starting point and B's position).
Since they are moving towards each other on the circular track (one clockwise, one anticlockwise), their relative speed is the sum of their speeds.
Relative speed = A's speed (anticlockwise) + B's speed (clockwise)
\( \text{Relative speed} = 4 \text{ m/s} + 6 \text{ m/s} = 10 \text{ m/s} \)
The time it takes for them to meet for the first time after \(t = 900\) seconds is the distance between them divided by their relative speed.
Time to meet = Distance between them / Relative speed
\( \text{Time after 900s to meet} = \frac{1800 \text{ m}}{10 \text{ m/s}} = 180 \text{ seconds} \)
The first meeting happens after A completes the first round and then runs for an additional 180 seconds while B continues running.
Total time = Time for A's first round + Time to meet after 900s
\( \text{Total time} = 900 \text{ s} + 180 \text{ s} = 1080 \text{ seconds} \)
They would cross for the first time 1080 seconds after starting the run.
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