The problem asks for the value of each of the two equal annual installments Somaraj paid to clear a loan of Rs. 11,550 at a 10% annual compound interest rate.
When a loan is repaid in equal installments, the sum of the present values of all installments must equal the original loan amount (principal). The present value of a future payment is calculated by discounting it back to the present using the interest rate.
Let:
The present value (PV) of the installments must equal the principal:
$ P = \frac{x}{(1+R)^1} + \frac{x}{(1+R)^2} $
Substitute the known values into the formula:
$ 11550 = \frac{x}{(1+0.10)^1} + \frac{x}{(1+0.10)^2} $
$ 11550 = \frac{x}{1.1} + \frac{x}{(1.1)^2} $
$ 11550 = \frac{x}{1.1} + \frac{x}{1.21} $
To solve for x, find a common denominator (1.21):
$ 11550 = \frac{1.1x}{1.21} + \frac{x}{1.21} $
$ 11550 = \frac{1.1x + x}{1.21} $
$ 11550 = \frac{2.1x}{1.21} $
Now, rearrange the equation to isolate x:
$ x = \frac{11550 \times 1.21}{2.1} $
$ x = \frac{13975.5}{2.1} $
$ x = 6655 $
The value of each annual installment is Rs. 6655.
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