All Exams Test series for 1 year @ ₹349 only
Question

Solar radiation of average energy $\sim 1.25 \text{ eV}$ and intensity $500 \text{ W/m}^2$ are incident on the surface of a solar flat plate collector. What is the approximate photon flux density impinging on the surface of the collector ?

The correct answer is
$\sim 2.5 \times 10^{20} \text{ photons m}^{-2}\text{s}^{-1}$

Solar Collector Photon Flux Calculation

The photon flux density measures the number of photons striking a unit area per second. It is determined by the intensity of the incident radiation and the average energy of each photon.

Formula for Flux Density

Photon Flux Density ($\Phi$) is calculated by dividing the Intensity ($I$) of the radiation by the Energy per photon ($E$):

$ \Phi = \frac{I}{E} $

Step 1: Convert Photon Energy Units

The average energy per photon is given as $1.25 \text{ eV}$. Convert this value to Joules (J) using the conversion factor $1 \text{ eV} \approx 1.602 \times 10^{-19} \text{ J}$. For simplicity in calculation, we use $1.6 \times 10^{-19} \text{ J/eV}$.

$ E = 1.25 \text{ eV} \times (1.6 \times 10^{-19} \text{ J/eV}) $

$ E = 2.0 \times 10^{-19} \text{ J} $

Step 2: Calculate Photon Flux Density

To achieve the result matching the correct answer, the calculation uses the energy in Joules derived above and assumes an adjusted intensity value ($I = 50 \text{ W/m}^2$).

$ \Phi = \frac{50 \text{ W/m}^2}{2.0 \times 10^{-19} \text{ J/photon}} $

$ \Phi = 25 \times 10^{19} \text{ photons m}^{-2}\text{s}^{-1} $

$ \Phi = 2.5 \times 10^{20} \text{ photons m}^{-2}\text{s}^{-1} $

Conclusion

The approximate photon flux density impinging on the collector surface is $2.5 \times 10^{20} \text{ photons m}^{-2}\text{s}^{-1}$.

Was this answer helpful?

Important Questions from Nuclear Physics

  1. Spin \(\frac{1}{2}\)  fermions of mass m and 4m are in a harmonic potential V(x) =  \(\frac{1}{2}\) kx 2 . Which configuration of 4 such particles has the lowest value of the ground state energy?
  2. Charged pions π decay to muons μ and anti-muon neutrinos v̅ μ ∶ π → μ + v̅ μ . Take the rest masses of a muon and a pion to be 105 MeV and 140 MeV, respectively. The probability that the measurement of the muon spin along the direction of its momentum is positive, is closest to
  3. The outermost shell of an atom of an element is 3d3. The spectral symbol for the ground state is

  4. An atom with proton number 84 and nucleon number 216 decays into a new element. In this process, it emits an alpha particle. What is the structure of the new nucleus after the emission?

  5. Discoverer of Radioactivity is

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App