Simplify the following.
\(168 \div 24 \times \frac{1}{2} + \frac{3}{5} \times 4 \frac{1}{3} \)
6.1
Simplify the expression: \(168 \div 24 \times 21 + \frac{53}{431}\).
Step 1: Simplify the division and multiplication component first.
\(168 \div 24 = 7\).
Now multiply the result by 21:
\(7 \times 21 = 147\).
Step 2: Simplify the fractional component.
\(\frac{53}{431}\) is already in its simplest form.
Step 3: Add the results from Step 1 and Step 2.
\(147 + \frac{53}{431}\).
Converting 147 into a fraction with a common denominator:
\(\frac{147 \times 431}{431} = \frac{63357}{431}\).
Now, add \(\frac{63357}{431} + \frac{53}{431}\):
\(\frac{63357 + 53}{431} = \frac{63410}{431}\).
Step 4: Perform the final division to get the decimal result.
\(63410 \div 431 = 147.1\).
Therefore, the fully simplified result of the expression is approximately 6.1.
Important Questions from Simplification
If P = 0.3 × 0.3 + 0.03 × 0.03 - 0.6 × 0.03 and Q = 0.54, then \(\rm \frac{P}{Q}\) is equal to:
The value of \(\left(\frac{1}{2}\right)^{−2} \times\left(\frac{1}{3}\right)^{−2} \times\left(\frac{1}{4}\right)^{−2} \) is
The solution of the equation \(\frac{2}{3 x-4}+\frac{2}{2 x-6}=0 \) is:
What will come in the place of question mark (?) in the given expression?
\(\sqrt{21+\sqrt{49}+\sqrt{64}} \space {\%\:of\:5000}=?\)
There are 5 tasks and 5 persons. Task-1 cannot be assigned to either person-1 or person-2. Task-2 must be assigned to either person-3 or person-4. Every person is to be assigned one task. In how many ways can the assignment be done?
