Simplify the expression \((\sqrt{81} + \sqrt{0.81} + \sqrt{0.0081})\sqrt{10000}.\)
Let's simplify the given mathematical expression step by step. The expression is \((\sqrt{81} + \sqrt{0.81} + \sqrt{0.0081})\sqrt{10000}.\) To simplify this, we need to calculate the value of each square root term first, then perform the addition inside the parentheses, and finally multiply the result by the value of the last square root.
We have three square roots inside the parentheses and one outside. Let's find the value of each one:
\(\sqrt{81} = 9\)
\(\sqrt{0.81} = \sqrt{\frac{81}{100}} = \frac{\sqrt{81}}{\sqrt{100}} = \frac{9}{10} = 0.9\)
\(\sqrt{0.0081} = \sqrt{\frac{81}{10000}} = \frac{\sqrt{81}}{\sqrt{10000}} = \frac{9}{100} = 0.09\)
\(\sqrt{10000} = 100\)
Now we replace the square roots in the original expression with their calculated values:
\((\sqrt{81} + \sqrt{0.81} + \sqrt{0.0081})\sqrt{10000} = (9 + 0.9 + 0.09) \times 100\)
Add the decimal numbers inside the parentheses:
\(9 + 0.9 + 0.09 = 9.99\)
So the expression becomes:
\((9.99) \times 100\)
Finally, multiply the sum by 100:
\(9.99 \times 100 = 999\)
The simplified value of the expression \((\sqrt{81} + \sqrt{0.81} + \sqrt{0.0081})\sqrt{10000}\) is 999.
| Square Root | Value |
|---|---|
| \(\sqrt{81}\) | 9 |
| \(\sqrt{0.81}\) | 0.9 |
| \(\sqrt{0.0081}\) | 0.09 |
| \(\sqrt{10000}\) | 100 |
| Concept | Explanation | Example |
|---|---|---|
| Square Root | A number that produces a given quantity when multiplied by itself. | \(\sqrt{25} = 5\) because \(5 \times 5 = 25\) |
| Square Root of Decimals | Convert decimal to fraction, find square roots of numerator and denominator. | \(\sqrt{0.04} = \sqrt{\frac{4}{100}} = \frac{\sqrt{4}}{\sqrt{100}} = \frac{2}{10} = 0.2\) |
| Square Root of Powers of 10 | \(\sqrt{10^n} = 10^{n/2}\). For even \(n\), the result is an integer power of 10. | \(\sqrt{100} = \sqrt{10^2} = 10^{2/2} = 10^1 = 10\), \(\sqrt{10000} = \sqrt{10^4} = 10^{4/2} = 10^2 = 100\) |
When calculating the square root of a decimal number, the number of decimal places in the result is half the number of decimal places in the original number. For example:
This rule helps you quickly check if your decimal square root calculation is likely correct based on the number of decimal places.
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