Simple interest on a certain sum at 8% per annum for 5 years is ₹2400. What will be the compound interest on the same sum at the same rate for 2 years?
₹998.40
This problem involves two key concepts in finance: simple interest and compound interest. Simple interest is calculated only on the initial principal amount, while compound interest is calculated on the principal amount and also on the accumulated interest from previous periods. This means compound interest grows faster than simple interest over time.
We are given the simple interest earned on a certain sum over a specific period at a fixed rate. We can use the formula for simple interest to find the original sum (principal). The formula for simple interest is:
\(\text{SI} = \frac{\text{P} \times \text{R} \times \text{T}}{100}\)
Where:
We are given:
Let's plug these values into the formula to find P:
\(2400 = \frac{\text{P} \times 8 \times 5}{100}\)
Simplify the equation:
\(2400 = \frac{40\text{P}}{100}\)
\(2400 = \frac{2\text{P}}{5}\)
Now, solve for P:
\(\text{P} = \frac{2400 \times 5}{2}\)
\(\text{P} = 1200 \times 5\)
\(\text{P} = 6000\)
So, the principal sum is ₹6000.
Now we need to calculate the compound interest on this principal amount (₹6000) at the same rate (8% per annum) for a period of 2 years. The formula for the amount (A) under compound interest is:
\(\text{A} = \text{P}\left(1 + \frac{\text{R}}{100}\right)^{\text{T}}\)
Where:
We know:
Substitute these values into the formula:
\(\text{A} = 6000\left(1 + \frac{8}{100}\right)^{2}\)
\(\text{A} = 6000\left(1 + 0.08\right)^{2}\)
\(\text{A} = 6000\left(1.08\right)^{2}\)
Calculate \((1.08)^2\):
\(1.08 \times 1.08 = 1.1664\)
Now, calculate the Amount (A):
\(\text{A} = 6000 \times 1.1664\)
\(\text{A} = 6998.40\)
The amount after 2 years with compound interest is ₹6998.40.
To find the compound interest (CI), subtract the principal from the amount:
\(\text{CI} = \text{A} - \text{P}\)
\(\text{CI} = 6998.40 - 6000\)
\(\text{CI} = 998.40\)
The compound interest on ₹6000 at 8% per annum for 2 years is ₹998.40.
The compound interest on the same sum (₹6000) at the same rate (8% per annum) for 2 years is ₹998.40.
| Detail | Simple Interest Calculation | Compound Interest Calculation |
|---|---|---|
| Principal (P) | Calculated as ₹6000 | ₹6000 |
| Rate (R) | 8% | 8% |
| Time (T) | 5 years | 2 years |
| Interest Earned | SI = ₹2400 (Given) | CI = ₹998.40 (Calculated) |
| Formula Used | \(\text{SI} = \frac{\text{P} \times \text{R} \times \text{T}}{100}\) | \(\text{A} = \text{P}\left(1 + \frac{\text{R}}{100}\right)^{\text{T}}\), CI = A - P |
| Concept | Formula | Notes |
|---|---|---|
| Simple Interest (SI) | \(\text{SI} = \frac{\text{P} \times \text{R} \times \text{T}}{100}\) | Interest is calculated only on the principal. |
| Amount (A) in Simple Interest | \(\text{A} = \text{P} + \text{SI} = \text{P}\left(1 + \frac{\text{R} \times \text{T}}{100}\right)\) | Total amount after T years. |
| Amount (A) in Compound Interest | \(\text{A} = \text{P}\left(1 + \frac{\text{R}}{100}\right)^{\text{T}}\) | Interest is compounded periodically (usually annually). |
| Compound Interest (CI) | \(\text{CI} = \text{A} - \text{P} = \text{P}\left[\left(1 + \frac{\text{R}}{100}\right)^{\text{T}} - 1\right]\) | Total interest earned after T years. |
Interest calculations are fundamental in personal finance, banking, and economics. Understanding the difference between simple and compound interest is crucial. Compound interest is often referred to as 'interest on interest' and is the basis for growth in savings, investments, and loans over longer periods.
Find the compound interest on ₹64000 at 10% per annum for 9 months when interest is compounded quarterly.
A man invested on simple interest, 1/4 of his capital at 7% p.a., another 1/4 of the capital at 8% p.a. and the remaining capital at 10% p.a. He earned Rs. 700 as interest in one year. Find his total capital invested.
A sum of money doubles itself in 10 years on compound interest. In how many years will it become four times?
A sum of ₹1500 is invested at 5% p.a. simple interest. If the interest is added to the principal after every 10 years, the amount will become ₹3000 after:
Find the compound interest on ₹42000 for 1½ years at 10% p.a. compounded annually.