Seven friends P, Q, R, S, T, U, and V are sitting in a straight line facing north. Q sits fifth to the right of T. Q does not sit at any of the extreme ends. Two people sit between U and R. S sits third to the left of V. S sits exactly in the middle. U is not an immediate neighbour of P. How many people sit between R and V?
Four
We are given clues about the seating arrangement of seven friends P, Q, R, S, T, U, and V sitting in a straight line facing North. We need to deduce their exact positions to answer the question.
Let's use the clues one by one to build the seating arrangement of the seven friends.
There are 7 positions in the line. The middle position is the 4th position.
Clue: S sits exactly in the middle.
| Position 1 | Position 2 | Position 3 | Position 4 | Position 5 | Position 6 | Position 7 |
|---|---|---|---|---|---|---|
| S |
Clue: S sits third to the left of V.
If S is at position 4, and S is to the left of V, V must be to the right of S. Being third to the left of V means V is third to the right of S.
So, V is at position ${4 + 3 = 7}$.
| Position 1 | Position 2 | Position 3 | Position 4 | Position 5 | Position 6 | Position 7 |
|---|---|---|---|---|---|---|
| S | V |
Clue: Q sits fifth to the right of T. This implies there are 4 people between T and Q (T _ _ _ _ Q).
Clue: Q does not sit at any of the extreme ends. The extreme ends are Position 1 and Position 7. Position 7 is already taken by V.
So Q cannot be at Position 1 or Position 7. The available positions are 1, 2, 3, 5, 6.
Let's try placing T and Q satisfying "Q is fifth to the right of T" and "Q is not at an end". If Q is at position 6 (not an end), then T would be at position ${6-5=1}$.
| Position 1 | Position 2 | Position 3 | Position 4 | Position 5 | Position 6 | Position 7 |
|---|---|---|---|---|---|---|
| T | S | Q | V |
This arrangement satisfies T _ _ _ _ Q (T at 1, Q at 6) and Q is not at an end.
Clue: Two people sit between U and R.
The remaining empty positions are 2, 3, and 5.
For two people to sit between U and R, U and R must be separated by two positions. The only pair of available positions that can have two people between them are positions 2 and 5 (with positions 3 and 4 in between). Since position 4 is taken by S, positions 2 and 5 must be where U and R sit.
| Position 1 | Position 2 | Position 3 | Position 4 | Position 5 | Position 6 | Position 7 |
|---|---|---|---|---|---|---|
| T | U/R | S | R/U | Q | V |
So, U and R are at positions 2 and 5 in some order.
The only person left to place is P, and the only empty position is 3.
| Position 1 | Position 2 | Position 3 | Position 4 | Position 5 | Position 6 | Position 7 |
|---|---|---|---|---|---|---|
| T | U/R | P | S | R/U | Q | V |
Now, let's use the last clue:
Clue: U is not an immediate neighbour of P.
P is at position 3. The immediate neighbours of P are at positions 2 and 4.
Position 4 is occupied by S, so S is a neighbour of P.
The person at position 2 is also a neighbour of P. According to the clue, U cannot be this neighbour.
Therefore, U cannot be at position 2. This means U must be at position 5, and R must be at position 2.
Replacing U and R based on the last clue, we get the final arrangement:
| Position 1 | Position 2 | Position 3 | Position 4 | Position 5 | Position 6 | Position 7 |
|---|---|---|---|---|---|---|
| T | R | P | S | U | Q | V |
Let's quickly verify all the clues with this final arrangement. All clues are satisfied by the arrangement T R P S U Q V.
The question asks: How many people sit between R and V?
In our final arrangement, R is at Position 2 and V is at Position 7.
The people sitting between Position 2 and Position 7 are those at positions 3, 4, 5, and 6.
Looking at the final arrangement (T R P S U Q V), the people between R and V are P, S, U, and Q.
Counting these individuals, we find there are 4 people between R and V.
Based on the step-by-step deduction and the final seating arrangement T R P S U Q V, there are four people sitting between R and V.
| Clue Used | Deduction/Placement | Partial Arrangement |
|---|---|---|
| S in the middle (Position 4) | S is at Pos 4 | _ _ _ S _ _ _ |
| S is 3rd left of V | V is at Pos ${4+3=7}$ | _ _ _ S _ _ V |
| Q is 5th right of T, Q not at ends | T at Pos 1, Q at Pos 6 | T _ _ S _ Q V |
| 2 people between U and R | U & R are at Pos 2 and Pos 5 | T (U/R) _ S (R/U) Q V |
| P takes remaining spot | P is at Pos 3 | T (U/R) P S (R/U) Q V |
| U is not neighbour of P | P neighbours are at 2 & 4. S is at 4. U cannot be at 2. So U is at 5, R is at 2. | T R P S U Q V |
Linear arrangement puzzles require careful reading and logical deduction. Here are some tips for solving them:
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