Understanding Letter-Cluster Analogies

In letter-cluster analogy questions, you need to find the relationship or pattern between the first two letter-clusters. Once you identify this pattern, you apply the same pattern to the third letter-cluster to find the answer.

Analyzing the First Letter-Cluster Pair: DILUTE to IDULET

Let's look closely at how the first letter-cluster, DILUTE, is transformed into the second letter-cluster, IDULET.

The letters in DILUTE are:

• D
• I
• L
• U
• T
• E

The letters in IDULET are:

• I
• D
• U
• L
• E
• T

Let's compare the positions of the letters:

From the table, we can see a clear pattern. The letters are swapped in pairs:

• The first two letters (DI) are swapped to become (ID).
• The next two letters (LU) are swapped to become (UL).
• The last two letters (TE) are swapped to become (ET).

So, the pattern is swapping each adjacent pair of letters in the original letter-cluster.

Applying the Pattern to the Third Letter-Cluster: FLIGHT

Now, we apply the same pattern of swapping adjacent pairs to the letter-cluster FLIGHT.

Let's break FLIGHT into pairs:

• The first pair is FL.
• The second pair is IG.
• The third pair is HT.

Now, swap the letters within each pair:

• FL becomes LF.
• IG becomes GI.
• HT becomes TH.

Combine the swapped pairs in order:

LF + GI + TH = LFGITH

Checking the Options

Let's compare our result, LFGITH, with the given options:

1. LFIGHT
2. ILFTHG
3. LFGITH
4. LFGHTI

Our derived letter-cluster, LFGITH, matches option 3.

Conclusion

The pattern observed between DILUTE and IDULET is the swapping of adjacent letter pairs. Applying this pattern to FLIGHT results in LFGITH.