Select the fraction that will be next in the following series.
2/3, 4/5, 6/7, 8/9, 10/11, 12/13,.....
14/15
The question asks us to find the next fraction in the given series:
\(\frac{2}{3}, \frac{4}{5}, \frac{6}{7}, \frac{8}{9}, \frac{10}{11}, \frac{12}{13}, \dots\)
To determine the next fraction, we need to identify the pattern in the sequence of fractions.
Let's examine the numerators and denominators of the fractions separately.
The sequence of numerators is:
\(2, 4, 6, 8, 10, 12, \dots\)
Observe the difference between consecutive terms:
The numerators form an arithmetic progression with a common difference of \(2\). To find the next numerator, we add \(2\) to the last numerator in the given series, which is \(12\).
\(\text{Next numerator} = 12 + 2 = 14\)
The sequence of denominators is:
\(3, 5, 7, 9, 11, 13, \dots\)
Observe the difference between consecutive terms:
The denominators also form an arithmetic progression with a common difference of \(2\). To find the next denominator, we add \(2\) to the last denominator in the given series, which is \(13\).
\(\text{Next denominator} = 13 + 2 = 15\)
The next fraction in the series will have the next numerator as its numerator and the next denominator as its denominator.
\(\text{Next fraction} = \frac{\text{Next numerator}}{\text{Next denominator}} = \frac{14}{15}\)
Let's compare the calculated next fraction with the given options:
| Option | Fraction |
|---|---|
| 1 | \(\frac{14}{15}\) |
| 2 | \(\frac{14}{16}\) |
| 3 | \(\frac{13}{15}\) |
| 4 | \(\frac{13}{14}\) |
The calculated next fraction, \(\frac{14}{15}\), matches Option 1.
The series follows a clear pattern where both the numerator and the denominator increase by \(2\) for each successive term. The numerator starts at \(2\), and the denominator starts at \(3\).
| Concept | Description | Example |
|---|---|---|
| Fraction Series | A sequence of fractions arranged according to a specific rule or pattern. | \(\frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \dots\) |
| Pattern Analysis | Examining the relationship between consecutive terms to find the rule governing the series. This often involves looking at numerators and denominators separately. | In \(\frac{2}{3}, \frac{4}{5}, \frac{6}{7}, \dots\), numerators are \(2, 4, 6, \dots\) and denominators are \(3, 5, 7, \dots\). |
| Arithmetic Progression | A sequence where the difference between consecutive terms is constant (common difference). | \(2, 4, 6, 8, \dots\) (common difference is 2) |
Sequences, whether of numbers or parts of fractions, can follow various patterns. Identifying the pattern is key to predicting future terms.
In this specific fraction series question, both the numerator and denominator sequences were simple arithmetic progressions.
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