This problem involves tracking the movement of Sanjeev in different directions and calculating his final position relative to his starting point. We need to find both the net distance and the direction.
Let's break down Sanjeev's journey step by step:
We first sum up all the movements along the East-West axis. Movement towards the East is considered positive, and West is negative.
Next, we sum up all the movements along the North-South axis. Movement towards the North is considered positive, and South is negative.
Sanjeev's final position is 9 km East and 12 km North of his starting point. These two displacements form the legs of a right-angled triangle. The distance from the starting point is the hypotenuse of this triangle. We can use the Pythagorean theorem to calculate this distance:
Let $d$ be the net distance from the starting point.
According to the Pythagorean theorem: $d^2 = (\text{Net Horizontal Displacement})^2 + (\text{Net Vertical Displacement})^2$
Substituting the values:
$$ d^2 = (9 \text{ km})^2 + (12 \text{ km})^2 $$ $$ d^2 = 81 \text{ km}^2 + 144 \text{ km}^2 $$ $$ d^2 = 225 \text{ km}^2 $$ $$ d = \sqrt{225 \text{ km}^2} $$ $$ d = 15 \text{ km} $$Since the net horizontal displacement is towards the East (9 km) and the net vertical displacement is towards the North (12 km), Sanjeev's final position relative to his starting point is in the North-East direction.
Combining the distance and direction, Sanjeev is 15 km away from his starting point in the North-East direction.
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