This problem involves tracking a person's movement through different directions and calculating their final distance from the starting point. Let's break down Rohan's journey step by step.
We can visualize Rohan's path or use coordinates to find his final position relative to his start.
Rohan starts at a point (let's call it the origin) and walks 3 kms towards North. His position is now 3 kms North of the start.
He turns to his left. Since he was facing North, his left is West. He walks 2 kms West. His position is now 3 kms North and 2 kms West of the start.
He again turns left. Now facing West, his left is South. He walks 3 kms South. This movement cancels out his initial 3 kms Northward movement. He is now on the same horizontal line as his starting point, but 2 kms West of it.
He turns left again. Facing South, his left is East. He walks for 3 kms. Starting from 2 kms West of the origin, walking 3 kms East means he first covers the 2 kms back to the starting point's North-South line, and then continues another 1 km East.
After the final step, Rohan is 1 km East of the North-South line passing through his starting point. Since his North-South displacement is zero (3 km North - 3 km South = 0 km), his final position is exactly 1 km East of his starting point.
Therefore, the distance from the starting point is simply this eastward displacement.
Final Distance = 1 km
Let the starting point be (0, 0).
The starting point is (0, 0) and the final point is (1, 0).
The distance using the distance formula:
Distance = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
Distance = $\sqrt{(1 - 0)^2 + (0 - 0)^2}$
Distance = $\sqrt{1^2 + 0^2}$
Distance = $\sqrt{1}$
Distance = $1$ km.
Both methods confirm that Rohan is 1 km away from his starting point.
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At the time of sunset, Lopa and Kritika are sitting facing each other. If the shadow of Lopa falls to the right of Kritika, in which direction is Kritika facing?