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Question

Reynolds number for non - circular cross-section is:

[V = mean velocity, ν = kinematic viscosity, P = ratio of cross-sectional area to the wetted perimeter]

A) \(V.\frac{{4P}}{v}\)

B) \(\frac{{V.P}}{v}\)

C) \(\frac{{V.2P}}{{4v}}\)

D) \(\frac{{V.P}}{{4v}}\)

The correct answer is

Only A

Understanding Reynolds Number for Non-Circular Cross-Sections

The Reynolds number (\(Re\)) is a dimensionless quantity that is used to predict flow patterns in different fluid flow situations. It describes the ratio of inertial forces to viscous forces and is commonly used to distinguish between laminar, transient, and turbulent flow.

For flow in a circular pipe, the Reynolds number is defined as:

\(Re = \frac{{\rho vD}}{{\mu}} = \frac{{vD}}{{\nu}}\)

where:

  • \(v\) is the mean velocity of the fluid.
  • \(D\) is the diameter of the pipe.
  • \(\rho\) is the density of the fluid.
  • \(\mu\) is the dynamic viscosity of the fluid.
  • \(\nu\) is the kinematic viscosity of the fluid (\(\nu = \mu / \rho\)).

For flow in non-circular cross-sections, such as rectangular ducts, annular spaces, or open channels, the concept of hydraulic diameter or hydraulic radius is used to calculate the Reynolds number. This allows us to use a similar formula structure as for circular pipes.

Defining Hydraulic Radius and Hydraulic Diameter

The hydraulic radius (\(R_h\)) is defined as the ratio of the cross-sectional area of the flow channel to the wetted perimeter.

\(R_h = \frac{{\text{Cross-sectional Area}}}{{\text{Wetted Perimeter}}}\)

The hydraulic diameter (\(D_h\)) is defined as four times the hydraulic radius.

\(D_h = 4 R_h\)

This definition is chosen such that for a circular pipe of diameter D, the hydraulic diameter is equal to D.

  • Area of circle = \(\frac{{\pi D^2}}{4}\)
  • Wetted perimeter of circle = \(\pi D\)
  • Hydraulic Radius \(R_h = \frac{{\pi D^2 / 4}}{{\pi D}} = \frac{D}{4}\)
  • Hydraulic Diameter \(D_h = 4 R_h = 4 \times \frac{D}{4} = D\)

Reynolds Number Formula for Non-Circular Sections

Using the hydraulic diameter, the Reynolds number for a non-circular cross-section is given by:

\(Re = \frac{{vD_h}}{{\nu}}\)

In the given question, the parameter P is defined as the ratio of the cross-sectional area to the wetted perimeter. This is exactly the definition of the hydraulic radius (\(R_h\)).

So, \(P = R_h\).

Substituting \(R_h\) in the hydraulic diameter formula, we get:

\(D_h = 4 R_h = 4P\)

Now, substituting this expression for \(D_h\) into the Reynolds number formula for non-circular sections:

\(Re = \frac{{v D_h}}{{\nu}} = \frac{{v (4P)}}{{\nu}}\)

\(Re = \frac{{4vP}}{{\nu}}\)

This can also be written as:

\(Re = v \cdot \frac{{4P}}{{\nu}}\)

Comparing with Options

Let's compare the derived formula with the given options, where \(V\) is used for mean velocity instead of \(v\).

A) \(V.\frac{{4P}}{v}\) - This matches our derived formula \(Re = V \cdot \frac{{4P}}{{\nu}}\).

B) \(\frac{{V.P}}{v}\) - This does not match.

C) \(\frac{{V.2P}}{{4v}}\) - This simplifies to \(\frac{{V.P}}{{2v}}\), which does not match.

D) \(\frac{{V.P}}{{4v}}\) - This does not match.

Therefore, the correct expression for the Reynolds number for a non-circular cross-section, using the given parameter P, is \(V.\frac{{4P}}{v}\).

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Important Questions from Dimensionless Number

  1. Match the following and select the correct answer from the codes given below the lists

    List I

    List II

    A.

    Steam Nozzle

    1.

    Mach number

    B.

    Compressible flow

    2.

    Reaction turbine

    C.

    Surface Tension

    3.

    Biot number

    D.

    Heat conduction

    4.

    Nusselt number

    5.

    Supersaturation

    6.

    Weber number

  2. The Reynold’s number, used for critical velocity for turbulent flow of fluids, is given by the relation

  3. When the Mach number is less than unity, the flow is

  4. The only possible dimensionless group that combines velocity ‘V’, body size ‘L’, fluid density ‘ρ’ & surface tension ‘σ’

  5. Which of the following is not a non-dimensional parameter?
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