(Left) $4\ 7\ 5\ 8\ 9\ 2\ 8\ 7\ 1\ 6\ 8\ 2\ 9\ 8\ 5\ 2\ 8\ 2\ 6\ 4\ 4\ 7\ 8$ (Right)
How many such odd digits are there each of which is immediately preceded by an odd digit and also immediately followed by an odd digit?
The question asks us to analyze a given number series to find the count of specific odd digits. The criteria are: the digit itself must be odd, it must be immediately preceded by an odd digit, and it must be immediately followed by an odd digit. We read the series from left to right.
First, let's recall the definitions:
We can represent the parity of digits using '$O$' for Odd and '$E$' for Even.
The number series provided is:
$4 7 5 8 9 2 8 7 1 6 8 2 9 8 5 2 8 2 6 4 4 7 8$
We are searching for the pattern '$O$ $O$ $O$' (Odd - Odd - Odd). The middle odd digit in such a sequence is the one we need to count.
Let's systematically check the series for any occurrence of three consecutive odd digits:
| Sequence | Parity | Pattern Found? ($O$ $O$ $O$) |
|---|---|---|
| 4 7 5 | $E$ $O$ $O$ | No |
| 7 5 8 | $O$ $O$ $E$ | No |
| 5 8 9 | $O$ $E$ $O$ | No |
| 8 9 2 | $E$ $O$ $E$ | No |
| 9 2 8 | $O$ $E$ $E$ | No |
| 2 8 7 | $E$ $E$ $O$ | No |
| 8 7 1 | $E$ $O$ $O$ | No |
| 7 1 6 | $O$ $O$ $E$ | No |
| 1 6 8 | $O$ $E$ $E$ | No |
| 6 8 2 | $E$ $E$ $E$ | No |
| 8 2 9 | $E$ $E$ $O$ | No |
| 2 9 8 | $E$ $O$ $E$ | No |
| 9 8 5 | $O$ $E$ $O$ | No |
| 8 5 2 | $E$ $O$ $E$ | No |
| 5 2 8 | $O$ $E$ $E$ | No |
| 2 8 2 | $E$ $E$ $E$ | No |
| 8 2 6 | $E$ $E$ $E$ | No |
| 2 6 4 | $E$ $E$ $E$ | No |
| 6 4 4 | $E$ $E$ $E$ | No |
| 4 4 7 | $E$ $E$ $O$ | No |
| 4 7 8 | $E$ $O$ $E$ | No |
As the table shows, there are no instances where three consecutive digits are all odd.
Since no sequence of '$O$ $O$ $O$' was found, there is no odd digit that satisfies both conditions (being preceded by an odd digit and followed by an odd digit). Therefore, the count is zero.