Refer to the number series given below and answer the question that follows. Counting to be done from left to right only. (All numbers are single-digit numbers only.)
(Left) 6 2 1 5 7 3 7 8 5 3 4 5 2 4 8 4 3 6 9 7 4 2 1 5 7 9 1 (Right)
How many such odd digits are there each of which is immediately preceded by an even digit and also immediately followed by an odd digit?
The given number series is: $6 2 1 5 7 3 7 8 5 3 4 5 2 4 8 4 3 6 9 7 4 2 1 5 7 9 1$
The question asks us to find the count of specific odd digits within this series. The criteria for counting an odd digit are:
Essentially, we are looking for the pattern: $Even Digit - Odd Digit - Odd Digit$. We need to count how many times the middle 'Odd Digit' in this specific sequence appears.
Let's analyze the series from left to right, looking for the $Even - Odd - Odd$ pattern:
By systematically checking the series against the required pattern (Even - Odd - Odd), we found exactly 4 instances that satisfy all the conditions.
The odd digits fulfilling the criteria are:
Therefore, the total count is 4.