Refer to the following series and answer the question that follows (all numbers are single digit numbers only). Counting to be done from left to right only. (Left) 9 1 8 6 9 1 8 4 8 2 6 9 7 2 6 5 9 8 4 7 1 9 1 6 9 6 5 (Right) How many such even numbers are there (from left to right) each of which is immediately preceded by an odd number and also immediately followed by an even number?
The problem asks us to count the occurrences of a specific pattern within a given series of single-digit numbers. The series is: 9 1 8 6 9 1 8 4 8 2 6 9 7 2 6 5 9 8 4 7 1 9 1 6 9 6 5.
We need to find the count of **even numbers** that satisfy two conditions simultaneously:
This means we are looking for the pattern: Odd Even Even.
Let's examine the series from left to right, looking for the pattern 'Odd Even Even':
By analyzing the series, we found 4 instances where an even number is preceded by an odd number and followed by an even number.
The numbers identified are: 8 (in 1 8 6), 8 (in 1 8 4), 2 (in 7 2 6), and 8 (in 9 8 4).
Therefore, the total count is 4.
The sum of five numbers is 655. The average of the first two numbers is 78 and the third number is 108. Find the average of the remaining two numbers?
Find the average of 320 , 330 , 340 .
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