Recessive lethal alleles are never completely eliminated from the population because:
they are maintained in the population as heterozygotes.
Let's understand why recessive lethal alleles can persist in a population despite their harmful effect when homozygous.
A lethal allele is one that causes the death of the organism possessing it. Recessive lethal alleles only cause death when an individual has two copies of the allele (is homozygous recessive). If an individual has only one copy of the recessive lethal allele and one copy of the dominant allele (is heterozygous), they typically survive and are phenotypically normal or at least not lethal.
Consider a gene locus with a recessive lethal allele 'l' and a dominant normal allele 'L'.
Individuals with the 'll' genotype die, so this genotype is removed from the population's breeding pool in each generation. However, individuals with the 'Ll' genotype survive and reproduce. These heterozygotes carry the recessive lethal allele 'l' and can pass it on to their offspring. Because heterozygotes are not affected by the lethal condition (they are viable), the recessive lethal allele remains hidden in the gene pool within these carrier individuals.
Over generations, while homozygous recessive individuals (ll) are eliminated, the allele 'l' is continuously reintroduced into the population through the reproduction of heterozygous carriers (Ll). This process prevents the complete elimination of the recessive lethal allele from the population.
Let's look at the given options in light of this understanding:
Therefore, recessive lethal alleles are never completely eliminated from the population because they are maintained in the population within heterozygous individuals who carry the allele but are not subject to its lethal effect.
Which one of the following conditions associated with chromosome 15 may cause Prader-Willi syndrome?
Red-blue colour blindness is a human X-linked recessive disorder. The two parents with normal colour vision have two sons. Son 1 has 47, XXY chromosome composition and is colour blind. Son 2 has 46, XY and is also colour blind. Assuming that no crossing over took place in prophase I of meiosis, Klinefelter syndrome in Son 1 resulted due to nondisjunction during which one of the following events?
Which one of the following is the most appropriate definition of 'Gene Pyramiding' in plants?
Centromere positions can be mapped in linear tetrads in some fungi. A cross was made between two strains a b and a b and 100 linear tetrads were analysed. The genes a and b are located on two arms of the chromosome. The tetrads were divided into 5 classes as shown below
Class | 1 | 2 | 3 | 4 | 5 |
a b | a b | a b | a b | a b | |
a b | a b | a b | a b | a b | |
a b | a b | a b | a b | a b | |
a b | a b | a b | a b | a b | |
Linear tetrads | 15 | 29 | 52 | 2 | 2 |
Based on the above observation, the following conclusions were drawn:
A. Class 1 is a result of a cross over between a' and the centromere
B. Class 2 is a result of a double crossover involving 3 strands between 'a' and the centromere
C. Class 5 is a result of a double crossover between 'a' - centromere, and 'b'- centromere, involving three strands
D. Class 4 is a result of a double crossover, involving all the 4 strands
Which one of the following options represents all correct statements?
A To transgenic plant contains two unlinked copies of the T-DNA of which, one is functional and the other is silenced. Segregation of the transgenic to non- transgenic phenotype would occur in a (i) ratio in progeny obtained by backcrossing and in a (ii) ratio in F1 progeny obtained by self-pollination.
Fill in the blanks with the correct combination of (i) and (ii) from the options given below: