Ram and Ramesh appeared in an interview for two vacancies in the same department. The probability of Ram’s selection is 1/6 and that of Ramesh is 1/8. What is the probability that only one of them will be selected?
1/4
In this problem, we are asked to find the probability that only one of the two candidates, Ram and Ramesh, will be selected for a job interview. We are given their individual probabilities of selection.
To solve this, we need to consider two distinct situations where only one person gets selected, and then sum their probabilities. First, let's list the given probabilities and calculate the probabilities of non-selection.
We are provided with the following probabilities for Ram's selection and Ramesh's selection:
Now, we need to find the probability that each candidate is not selected. The probability of an event not occurring is \(1\) minus the probability of the event occurring.
The problem asks for the probability that only one of them will be selected. This can happen in two mutually exclusive ways:
We will calculate the probability for each of these selection scenarios.
Since the selection events are independent, we multiply their individual probabilities:
\( P(\text{Ram selected and Ramesh not selected}) = P(R) \times P(M') \)
\( = \frac{1}{6} \times \frac{7}{8} \)
\( = \frac{1 \times 7}{6 \times 8} \)
\( = \frac{7}{48} \)
Similarly, for this scenario, we multiply their individual probabilities:
\( P(\text{Ramesh selected and Ram not selected}) = P(M) \times P(R') \)
\( = \frac{1}{8} \times \frac{5}{6} \)
\( = \frac{1 \times 5}{8 \times 6} \)
\( = \frac{5}{48} \)
To find the total probability that only one of them will be selected, we add the probabilities of these two mutually exclusive scenarios:
\( P(\text{Only one selected}) = P(\text{Ram selected and Ramesh not selected}) + P(\text{Ramesh selected and Ram not selected}) \)
\( = \frac{7}{48} + \frac{5}{48} \)
\( = \frac{7 + 5}{48} \)
\( = \frac{12}{48} \)
Finally, we simplify the fraction:
\( = \frac{12 \div 12}{48 \div 12} \)
\( = \frac{1}{4} \)
Thus, the probability that only one of Ram or Ramesh will be selected is \( \frac{1}{4} \).
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