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Question

Radiocarbon activity in a sample is found to be 1/4 of the initial activity. If the half-life of the radiocarbon is 5700 years, then the age (in years) of the sample is

The correct answer is
11400

Understanding Radiocarbon Activity Decrease

The question states that the radiocarbon activity in a sample is now 1/4 of its initial activity. This means the amount of radioactive carbon has reduced significantly over time.

We are given the half-life of radiocarbon ($T_{1/2}$) as 5700 years. The half-life is the time it takes for half of the radioactive substance to decay.

Calculating Sample Age from Activity

Since the activity is 1/4 of the initial value, we can determine how many half-lives have passed:

  • After 1 half-life: Activity = 1/2 of initial.
  • After 2 half-lives: Activity = 1/2 of (1/2) = 1/4 of initial.

Therefore, 2 half-lives have passed for the activity to become 1/4 of the initial amount.

Determining the Total Age

To find the total age of the sample, we multiply the number of half-lives by the duration of one half-life:

Age ($t$) = Number of half-lives $\times$ Half-life duration ($T_{1/2}$)

Age ($t$) = $2 \times 5700 \text{ years}$

Age ($t$) = $11400 \text{ years}$

The age of the sample is 11400 years.

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Important Questions from Radioactive Isotopes

  1. Bomb - produced radiocarbon activity in the atmosphere is
  2. Which of the following isotopes would be the most useful to study the Earth process that has time scales of $1000\text{ years}$?
  3. Which one of the following isotope dating methods is based on the parent isotope abundances and not on the daughter isotope abundances?
  4. Which one of the following radioactive isotope systems has been used for estimation of the age of core formation event in the Earth?
  5. Match the paleoclimatic archive with most appropriate dating method.

    ArchiveDating Method
    (A) Speleothem(E) Radiocarbon
    (B) Tree rings(F) U-series
    (C) Ice Core(G) Optically Stimulated Luminescence
    (D) Sand dunes(H) $^{210}\text{Pb}$
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