The question states that the radiocarbon activity in a sample is now 1/4 of its initial activity. This means the amount of radioactive carbon has reduced significantly over time.
We are given the half-life of radiocarbon ($T_{1/2}$) as 5700 years. The half-life is the time it takes for half of the radioactive substance to decay.
Since the activity is 1/4 of the initial value, we can determine how many half-lives have passed:
Therefore, 2 half-lives have passed for the activity to become 1/4 of the initial amount.
To find the total age of the sample, we multiply the number of half-lives by the duration of one half-life:
Age ($t$) = Number of half-lives $\times$ Half-life duration ($T_{1/2}$)
Age ($t$) = $2 \times 5700 \text{ years}$
Age ($t$) = $11400 \text{ years}$
The age of the sample is 11400 years.
| Archive | Dating Method |
|---|---|
| (A) Speleothem | (E) Radiocarbon |
| (B) Tree rings | (F) U-series |
| (C) Ice Core | (G) Optically Stimulated Luminescence |
| (D) Sand dunes | (H) $^{210}\text{Pb}$ |