Point A is $30$ m to the North of point B. Point A is $10$ m to the west of point C. Point C is $20$m to the North of point D. Point E is $20$ m to the East of point D. Point F is $20$ m to the South of point E. What is the shortest distance from the point B to point E.
To find the shortest distance between point B and point E, we can use coordinate geometry. We need to determine the coordinates of both points based on the given relative positions.
Let's establish a coordinate system. A convenient starting point is to place point B at the origin (0, 0).
Now, let's find the coordinates of the other points step-by-step:
Point A is 30 m to the North of point B. In a coordinate system where North is the positive y-direction, this means:
Point A is 10 m to the West of point C. This means point C is 10 m to the East of point A. East corresponds to the positive x-direction.
Point C is 20 m to the North of point D. This means point D is 20 m to the South of point C. South corresponds to the negative y-direction.
Point E is 20 m to the East of point D. East corresponds to the positive x-direction.
(Note: The information about point F is not needed to calculate the distance between B and E.)
The shortest distance between two points in a plane is a straight line. We can calculate this using the distance formula, which is derived from the Pythagorean theorem. The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is:
$ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} $Using the coordinates of B=(0, 0) and E=(30, 10):
Substitute these values into the distance formula:
$ d_{BE} = \sqrt{(30 - 0)^2 + (10 - 0)^2} $ $ d_{BE} = \sqrt{(30)^2 + (10)^2} $ $ d_{BE} = \sqrt{900 + 100} $ $ d_{BE} = \sqrt{1000} $To simplify the square root:
$ d_{BE} = \sqrt{100 \times 10} $ $ d_{BE} = \sqrt{100} \times \sqrt{10} $ $ d_{BE} = 10\sqrt{10} \, \text{m} $| Point | Coordinates (x, y) |
|---|---|
| B | (0, 0) |
| A | (0, 30) |
| C | (10, 30) |
| D | (10, 10) |
| E | (30, 10) |
The shortest distance calculated between point B and point E is $10\sqrt{10}$ meters.
Rakesh left home and walked $5$km southwards, then turned right and walked $2$km and again turned right and walked $5$ km and finally again turned left and walked $5$ km. The shortest distance between the final position and home is.
I starts from Point A and drives 5 km towards the north. He then takes a right turn, drives 2 km, turns right and drives 9 km. He then takes a right turn and drives 7 km. He takes a final right turn, drives 4 km and stops at Point P. How far (shortest distance) and towards which direction should he drive in order to reach Point A again? (All turns are $90^\circ$ turns only unless specified.)