Pinky walks a distance 600m towards east, turns left moves 500m, then again turns left and walks 600m and then turns left again and moves 500m and halts. At what distance (in meters) is she from the starting point?
0
This problem involves analyzing movement in different directions. We need to find the final distance from the starting point after a series of movements and turns. Let's trace Pinky's path step by step.
Pinky starts at a certain point. Let's call this the starting point (S).
Let's look at the movements along the East-West axis and the North-South axis separately.
Imagine setting up a coordinate system with the starting point at (0,0). East is the positive x-direction, North is the positive y-direction, West is the negative x-direction, and South is the negative y-direction.
| Step | Direction | Distance (m) | Change in Position (x, y) | Current Position (relative to Start) |
|---|---|---|---|---|
| Start | - | 0 | (0, 0) | (0, 0) |
| 1 | East | 600 | (+600, 0) | (+600, 0) |
| 2 (Left turn) | North | 500 | (0, +500) | (+600, +500) |
| 3 (Left turn) | West | 600 | (-600, 0) | (+600 - 600, +500) = (0, +500) |
| 4 (Left turn) | South | 500 | (0, -500) | (0, +500 - 500) = (0, 0) |
After the four steps, Pinky's final position is (0,0) relative to the starting point, which was also at (0,0).
The distance from the starting point is the straight-line distance between the starting position and the final position. The starting position is (0,0) and the final position is (0,0).
The distance (d) between two points $(x_1, y_1)$ and $(x_2, y_2)$ in a 2D plane is given by the distance formula:
\(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
In this case, $(x_1, y_1) = (0,0)$ and $(x_2, y_2) = (0,0)$.
\(d = \sqrt{(0 - 0)^2 + (0 - 0)^2}\)
\(d = \sqrt{0^2 + 0^2}\)
\(d = \sqrt{0 + 0}\)
\(d = \sqrt{0}\)
\(d = 0\)
The distance from the starting point is 0 meters.
The movements effectively cancelled each other out, bringing Pinky back to her original starting location. The total distance travelled is \(600m + 500m + 600m + 500m = 2200m\), but the distance from the starting point (displacement) is 0m.
| Concept | Explanation | How it applies here |
|---|---|---|
| Distance Traveled | The total length of the path covered during movement. | Total distance = 600m + 500m + 600m + 500m = 2200m. |
| Displacement | The straight-line distance and direction from the starting point to the ending point. It's a vector quantity. | The ending point is the same as the starting point, so displacement is 0m. |
| Left Turn (in Directions) | From East, Left is North. From North, Left is West. From West, Left is South. From South, Left is East. | Used to determine the direction of movement after each turn. |
Solving directional problems often involves visualizing the path or using coordinates. Key things to remember:
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