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Question

Penetrating power of X-rays does not depend on:

The correct answer is

Current in the filament

Understanding X-ray Penetrating Power

The penetrating power of X-rays refers to their ability to pass through various materials. Hard X-rays (higher energy) have greater penetrating power than soft X-rays (lower energy).

Let's examine how each factor influences the properties of X-rays and, consequently, their penetrating power.

Factors Affecting X-ray Properties

  • Wavelength ($\lambda$) and Energy (E): The energy of an X-ray photon is inversely proportional to its wavelength. This relationship is given by the equation $\text{E} = \text{hc}/\lambda$, where h is Planck's constant and c is the speed of light. Higher energy photons have shorter wavelengths and are more penetrating. Therefore, penetrating power depends on both wavelength and energy.
  • Potential Difference: In an X-ray tube, electrons are accelerated across a potential difference (V) before striking a target. The maximum kinetic energy gained by an electron is given by $\text{E}_\text{max} = \text{eV}$, where e is the charge of the electron. When these high-energy electrons interact with the target, they produce X-rays. The maximum energy of the X-ray photons produced is equal to the maximum kinetic energy of the electrons, i.e., $\text{E}_\text{max, photon} = \text{eV}$. This maximum energy corresponds to the minimum wavelength ($\lambda_\text{min}$) of the X-ray spectrum, given by $\text{eV} = \text{hc}/\lambda_\text{min}$. A higher potential difference results in higher energy electrons, producing X-rays with higher maximum energy and shorter minimum wavelength. These higher-energy, shorter-wavelength X-rays have greater penetrating power. Thus, penetrating power depends on the potential difference.
  • Current in the Filament: The filament in an X-ray tube is heated by an electric current. This heating causes electrons to be emitted from the filament (thermionic emission). The magnitude of the filament current determines the rate of electron emission, which means a higher filament current releases more electrons per second. These electrons are then accelerated towards the target by the potential difference. A greater number of electrons hitting the target per second leads to the production of more X-ray photons, increasing the intensity (or quantity) of the X-ray beam. However, the filament current primarily affects the *number* of X-ray photons produced, not their individual *energy* or the distribution of energies within the beam (which are determined mainly by the potential difference and target material). Since penetrating power is related to the energy (or 'hardness') of the X-rays, the filament current does not significantly affect the penetrating power.

Summary of Dependencies

We can summarize the effect of each factor:

Factor Effect on X-rays Effect on Penetrating Power
Wavelength ($\lambda$) Lower $\lambda$ means Higher Energy Higher penetrating power for lower $\lambda$
Energy (E) Higher E means Higher Penetration Higher penetrating power for higher E
Potential Difference (V) Higher V means Higher max Energy ($\text{E}_\text{max}$) and lower min wavelength ($\lambda_\text{min}$) Higher penetrating power for higher V
Current in the Filament Higher current means more electrons, higher X-ray Intensity (Quantity) Does NOT significantly affect penetrating power (Quality/Energy)

Therefore, the penetrating power of X-rays depends on wavelength, energy, and potential difference but does not depend on the current in the filament.

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Important Questions from Electromagnetic Spectrum

  1. For X-rays and white sunlight:

  2. Match List I with List II

    List – I

    List – II

    US New Military Bands for Microwaves

    Frequency range in GHz

    A.

    H band

    I.

    2.000 ‐ 3.000 GHz

    B.

    J band

    II.

    4.000 ‐ 6.000 GHz

    C.

    G band

    III.

    6.000 ‐ 8.000 GHz

    D.

    E band

    IV.

    10.000 ‐ 20.000 GHz

    Choose the correct answer from the options given below:

  3. As the wavelength is increased from violet to red, the luminosity

  4. The wave number of the limiting line of the series (visible) in hydrogen spectrum is:

  5. Which one of the following is not an example of electromagnetic waves?

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