Oxidation states of which oxides of halogens are not the same? A) ClO2 B) Cl2O3 C) BrO2 D) I2O4 E) I2O5 Choose the correct answer from the options given below:
(B) and (E) only
Oxidation state, also known as oxidation number, is a hypothetical charge an atom would have if all bonds to atoms of different elements were 100% ionic. To determine the oxidation state of the halogen in these oxides, we use the common oxidation state of oxygen, which is typically -2, except in peroxides or superoxides (which these are not). The sum of the oxidation states of all atoms in a neutral compound is zero.
Let's calculate the oxidation state for the halogen in each given oxide:
\begin{equation*} x + 2 \times (-2) = 0 \end{equation*}
\begin{equation*} x - 4 = 0 \end{equation*}
\begin{equation*} x = +4 \end{equation*}
The oxidation state of Cl in ClO2 is +4.\begin{equation*} 2x + 3 \times (-2) = 0 \end{equation*}
\begin{equation*} 2x - 6 = 0 \end{equation*}
\begin{equation*} 2x = 6 \end{equation*}
\begin{equation*} x = +3 \end{equation*}
The oxidation state of Cl in Cl2O3 is +3.\begin{equation*} x + 2 \times (-2) = 0 \end{equation*}
\begin{equation*} x - 4 = 0 \end{equation*}
\begin{equation*} x = +4 \end{equation*}
The oxidation state of Br in BrO2 is +4.\begin{equation*} 2x + 4 \times (-2) = 0 \end{equation*}
\begin{equation*} 2x - 8 = 0 \end{equation*}
\begin{equation*} 2x = 8 \end{equation*}
\begin{equation*} x = +4 \end{equation*}
The oxidation state of I in I2O4 is +4.\begin{equation*} 2x + 5 \times (-2) = 0 \end{equation*}
\begin{equation*} 2x - 10 = 0 \end{equation*}
\begin{equation*} 2x = 10 \end{equation*}
\begin{equation*} x = +5 \end{equation*}
The oxidation state of I in I2O5 is +5.Here is a summary of the oxidation states:
| Oxide | Halogen | Oxidation State of Halogen |
|---|---|---|
| ClO2 (A) | Cl | +4 |
| Cl2O3 (B) | Cl | +3 |
| BrO2 (C) | Br | +4 |
| I2O4 (D) | I | +4 |
| I2O5 (E) | I | +5 |
The question asks which pair of these halogen oxides has oxidation states for the halogens that are not the same (i.e., are different). Let's look at the options provided:
Oxidation state of Cl in ClO2 is +4.
Oxidation state of I in I2O5 is +5.
The oxidation states (+4 and +5) are different.
Oxidation state of Cl in Cl2O3 is +3.
Oxidation state of I in I2O5 is +5.
The oxidation states (+3 and +5) are different.
Oxidation state of Br in BrO2 is +4.
Oxidation state of I in I2O4 is +4.
The oxidation states (+4 and +4) are the same.
Oxidation state of I in I2O4 is +4.
Oxidation state of I in I2O5 is +5.
The oxidation states (+4 and +5) are different.
Based on the calculations, the pair Cl2O3 and I2O5 has halogen oxidation states of +3 and +5, respectively. These oxidation states are not the same.
| Halogen Oxide | Chemical Formula | Halogen Oxidation State |
|---|---|---|
| Chlorine dioxide | ClO2 | +4 |
| Dichlorine trioxide | Cl2O3 | +3 |
| Bromine dioxide | BrO2 | +4 |
| Diiodine tetraoxide | I2O4 | +4 |
| Diiodine pentaoxide | I2O5 | +5 |
Halogens (Fluorine, Chlorine, Bromine, Iodine, Astatine) are in Group 17 of the periodic table. While Fluorine almost always has an oxidation state of -1 in its compounds, other halogens can exhibit a variety of positive oxidation states when bonded to more electronegative elements like oxygen.
Common positive oxidation states for Cl, Br, and I in oxides and oxyacids include +1, +3, +4, +5, and +7. Examples:
The specific oxidation state depends on the number of oxygen atoms bonded and the overall charge of the species (if it's an ion).
Second most abundant element in alloy misch metal is:
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Gel | (I) Hair cream |
| (B) Foam | (II) Dust |
| (C) Emulsion | (III) Cheese |
| (D) Aerosol | (IV) Whipped cream |
Choose the correct answer from the options given below:
Rate of a reaction changes from 2.48 × 10⁻³ mol⁻¹ sec⁻¹ to 4.96 × 10⁻³ mol⁻¹ sec⁻¹ when concentration of reactant is changed from 0.6 M to 2.4 M respectively, the order of reaction is:
Degree of dissociation, when molar conductivity of X at its concentration C is 24.14 and its limiting molar conductivity is 48.28 will be:
A divalent ion of 'V' (Atomic no. 23) in aqueous solution is: