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Question

Optical fiber uses reflection to guide light through a channel, in which angle of incidence is ________ the critical angle.

The correct answer is
greater than

Optical Fiber Reflection: Angle of Incidence Condition

Optical fibers guide light using the principle of Total Internal Reflection (TIR). This phenomenon occurs when light travels from a denser medium to a less dense medium.

For TIR to happen, the light ray must strike the boundary between the two media at an angle of incidence that meets a specific condition relative to the critical angle ($\theta_c$).

The condition for TIR is:

  • Angle of Incidence ($\theta_i$) must be greater than the Critical Angle ($\theta_c$). Mathematically, $\theta_i > \theta_c$.

When $\theta_i > \theta_c$, the light does not refract into the less dense medium but is entirely reflected back into the denser medium (the fiber core). This process repeats along the fiber's length, effectively guiding the light.

If the angle of incidence were less than or equal to the critical angle, the light would refract out of the fiber or escape at the boundary, failing to propagate.

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Important Questions from Optical Fiber

  1. Fibre optic power meters have input for attaching fiber optic connector and detector:

  2. The material used for making optic-fibre cable in general is-

  3. Multimode step-index fiber with a core diameter of 80 μm and a relative index difference of 1.5% is operating at a wavelength of 0.85 μm. If the core refractive index is 1.48, then the normalized frequency for the fiber is

  4. In a multimode fiber (step index), number of modes passing at an operating wavelength of 1300 nm are 1000, the refractive index of the core is 1.50 and that of the cladding is 1.48. The value of core diameter is:

  5. In optical fibers, the Rayleigh scattering is proportional to:

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