The problem involves two pipes, one filling a tank and the other emptying it. We need to find the time it takes to fill two-thirds of the tank when both pipes operate simultaneously.
When both pipes are open, the net rate at which the tank fills is the difference between the filling rate and the emptying rate.
Net filling rate = (Filling Pipe Rate) - (Emptying Pipe Rate)
Net filling rate = $\frac{1}{18} - \frac{1}{72}$
To subtract these fractions, find a common denominator, which is 72:
Net filling rate = $\frac{4}{72} - \frac{1}{72} = \frac{3}{72}$ tank/min
Simplifying the net rate:
Net filling rate = $\frac{1}{24}$ tank/min
The net rate tells us that $\frac{1}{24}$ of the tank is filled every minute. Therefore, the entire tank would be filled in 24 minutes (since Time = Total Work / Rate = 1 / (1/24) = 24 minutes).
We need to find the time required to fill only two-thirds ($\frac{2}{3}$) of the tank.
Time to fill $\frac{2}{3}$ of the tank = (Total time to fill the tank) $\times$ (Fraction of the tank to fill)
Time = $24 \text{ min} \times \frac{2}{3}$
Time = $\frac{24 \times 2}{3} \text{ min}$
Time = $8 \times 2 \text{ min}$
Time = $16 \text{ min}$
It will take 16 minutes to fill two-thirds of the tank when both pipes are operated together.
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