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Question

One of the diagonals of a rhombus is 70 percent of the other diagonal. What is the ratio of the area of rhombus to the square of the length of the larger diagonal?

The correct answer is

20

Understanding the Rhombus and Diagonals

A rhombus is a quadrilateral where all four sides are equal in length. A key property of a rhombus is that its diagonals bisect each other at right angles. The area of a rhombus can be calculated using the lengths of its diagonals.

Let the lengths of the two diagonals of the rhombus be $d_1$ and $d_2$. The formula for the area of a rhombus is:

Area $= \frac{1}{2} \times d_1 \times d_2$

Relating the Rhombus Diagonals

The problem states that one of the diagonals is 70 percent of the other. Let's assume $d_1$ is the larger diagonal and $d_2$ is the smaller diagonal. According to the question:

$d_2 = 70\%$ of $d_1$

To work with this percentage, we convert it to a decimal or a fraction:

$70\% = \frac{70}{100} = 0.7$ or $\frac{7}{10}$

So, the relationship between the diagonals is:

$d_2 = 0.7 \times d_1$

Calculating the Area in terms of the Larger Diagonal

Now, we substitute the expression for $d_2$ into the area formula:

Area $= \frac{1}{2} \times d_1 \times d_2$

Area $= \frac{1}{2} \times d_1 \times (0.7 d_1)$

Area $= \frac{1}{2} \times 0.7 \times d_1^2$

Area $= 0.5 \times 0.7 \times d_1^2$

Area $= 0.35 \times d_1^2$

So, the area of the rhombus is $0.35$ times the square of the length of the larger diagonal.

Finding the Ratio of Area to Square of Larger Diagonal

The question asks for the ratio of the area of the rhombus to the square of the length of the larger diagonal. This can be written as:

Ratio $= \frac{\text{Area}}{(\text{Larger Diagonal})^2}$

Ratio $= \frac{0.35 \times d_1^2}{d_1^2}$

The term $d_1^2$ cancels out from the numerator and denominator (assuming $d_1 \neq 0$, which must be true for a rhombus to exist):

Ratio $= 0.35$

Expressing the Ratio as a Fraction

The ratio $0.35$ needs to be expressed as a fraction to match the options. We convert the decimal to a fraction:

$0.35 = \frac{35}{100}$

Now, we simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 5:

Numerator: $35 \div 5 = 7$

Denominator: $100 \div 5 = 20$

So, the simplified fraction is $\frac{7}{20}$.

The ratio of the area of the rhombus to the square of the length of the larger diagonal is $7:20$.

Conclusion on Rhombus Area Ratio

Based on the calculations, the ratio of the area of the rhombus to the square of the length of the larger diagonal is $7:20$. This matches one of the given options.

Revision Table: Key Rhombus Concepts

ConceptDescriptionFormula/Property
Rhombus DefinitionA quadrilateral with four equal sides.All sides equal length
Diagonals of RhombusBisect each other at 90 degrees.Perpendicular bisectors
Area of RhombusSpace enclosed by the rhombus boundary.$\frac{1}{2} \times d_1 \times d_2$
Percentage ConversionExpressing a percentage as a decimal or fraction.$70\% = 0.7 = \frac{7}{10}$
RatioComparison of two quantities.a : b or a/b

Additional Information on Rhombus Properties

Besides the area formula using diagonals, here are some other important properties of a rhombus that might be useful in related problems:

  • All sides are congruent.
  • Opposite sides are parallel (a rhombus is a type of parallelogram).
  • Opposite angles are equal.
  • Adjacent angles are supplementary (sum up to 180 degrees).
  • The diagonals bisect the angles of the rhombus.
  • The perimeter of a rhombus is $4 \times \text{side length}$.
  • The rhombus is formed by two congruent triangles sharing a base side, or four congruent right-angled triangles formed by the diagonals.
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Important Questions from Mensuration

  1. A solid cube is painted yellow, blue and black such that opposite faces are of same colour. The cube is then cut into 36 cubes of two different sizes such that 32 cubes are small and the other four cubes are Big. None of the faces of the bigger cubes is painted blue. How many cubes have only one face painted?

  2. A and B are two heavy steel blocks. If B is placed on the top of A, the weight increases by 60%. How much weight will reduce with respect to the total weight of A and B, if B is removed from the top of A?

  3. A gardener increased the area of his rectangular garden by increasing its length by 40% and decreasing its width by 20%. The area of the new garden

  4. A village having a population of 4000 requires 150 liters of water per head per day. It has a tank measuring 20 m x 15 m x 6 m. The water of this tank will last for

  5. The centroid of an equilateral triangle ABC is G. If AB is 6 cms, the length of AG is

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