One of the diagonals of a rhombus is 70 percent of the other diagonal. What is the ratio of the area of rhombus to the square of the length of the larger diagonal?
7 ∶ 20
A rhombus is a quadrilateral where all four sides are equal in length. A key property of a rhombus is that its diagonals bisect each other at right angles. The area of a rhombus can be calculated using the lengths of its diagonals.
Let the lengths of the two diagonals of the rhombus be $d_1$ and $d_2$. The formula for the area of a rhombus is:
Area $= \frac{1}{2} \times d_1 \times d_2$
The problem states that one of the diagonals is 70 percent of the other. Let's assume $d_1$ is the larger diagonal and $d_2$ is the smaller diagonal. According to the question:
$d_2 = 70\%$ of $d_1$
To work with this percentage, we convert it to a decimal or a fraction:
$70\% = \frac{70}{100} = 0.7$ or $\frac{7}{10}$
So, the relationship between the diagonals is:
$d_2 = 0.7 \times d_1$
Now, we substitute the expression for $d_2$ into the area formula:
Area $= \frac{1}{2} \times d_1 \times d_2$
Area $= \frac{1}{2} \times d_1 \times (0.7 d_1)$
Area $= \frac{1}{2} \times 0.7 \times d_1^2$
Area $= 0.5 \times 0.7 \times d_1^2$
Area $= 0.35 \times d_1^2$
So, the area of the rhombus is $0.35$ times the square of the length of the larger diagonal.
The question asks for the ratio of the area of the rhombus to the square of the length of the larger diagonal. This can be written as:
Ratio $= \frac{\text{Area}}{(\text{Larger Diagonal})^2}$
Ratio $= \frac{0.35 \times d_1^2}{d_1^2}$
The term $d_1^2$ cancels out from the numerator and denominator (assuming $d_1 \neq 0$, which must be true for a rhombus to exist):
Ratio $= 0.35$
The ratio $0.35$ needs to be expressed as a fraction to match the options. We convert the decimal to a fraction:
$0.35 = \frac{35}{100}$
Now, we simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 5:
Numerator: $35 \div 5 = 7$
Denominator: $100 \div 5 = 20$
So, the simplified fraction is $\frac{7}{20}$.
The ratio of the area of the rhombus to the square of the length of the larger diagonal is $7:20$.
Based on the calculations, the ratio of the area of the rhombus to the square of the length of the larger diagonal is $7:20$. This matches one of the given options.
| Concept | Description | Formula/Property |
|---|---|---|
| Rhombus Definition | A quadrilateral with four equal sides. | All sides equal length |
| Diagonals of Rhombus | Bisect each other at 90 degrees. | Perpendicular bisectors |
| Area of Rhombus | Space enclosed by the rhombus boundary. | $\frac{1}{2} \times d_1 \times d_2$ |
| Percentage Conversion | Expressing a percentage as a decimal or fraction. | $70\% = 0.7 = \frac{7}{10}$ |
| Ratio | Comparison of two quantities. | a : b or a/b |
Besides the area formula using diagonals, here are some other important properties of a rhombus that might be useful in related problems:
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