$6×10^{18}$ electrons
The question asks us to find the number of electrons equivalent to one coulomb (C) of charge. We know that charge is quantized, meaning it exists in discrete units. The fundamental unit of charge is the charge of a single electron (or proton).
The charge of a single electron ($e$) is approximately $1.602 \times 10^{-19}$ Coulombs.
To find the number of electrons ($n$) that make up one coulomb ($Q$) of charge, we can use the formula:
$ Q = n \times e $
Rearranging the formula to solve for $n$:
$ n = \frac{Q}{e} $
Substitute the given values:
Now, perform the calculation:
$ n = \frac{1 \, \text{C}}{1.602 \times 10^{-19} \, \text{C/electron}} $
$ n \approx 6.24 \times 10^{18} \, \text{electrons} $
The calculated value is approximately $6.24 \times 10^{18}$ electrons. Comparing this to the given options:
Option 2, $6 \times 10^{18}$ electrons, is the closest approximation to our calculated value.
Which of the following expressions correctly represents the SI unit of electric charge, the Coulomb ($C$), in terms of other fundamental or derived SI units?
Two point charges, $Q_1 = +3 \mu C$ and $Q_2 = -8 \mu C$, are placed at a certain distance apart. They attract each other with a force of $48 N$. If each charge is given an additional charge of $+6 \mu C$, what will be the magnitude and nature of the new force between them?