Munaf and Surya start simultaneously at the same point on a circular track and run along the track in the same direction. The point on the track at which they meet for the 31st time is the same as that at which they meet for the 43rd time. If the ratio of the speed of the faster boy to that of the slower one is n ∶ 1, where ‘n’ is a natural number, which of the following is NOT a possible value of ‘n’?
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This problem involves two runners, Munaf and Surya, starting at the same point on a circular track and running in the same direction. We are given information about when they meet at the same point on the track and the ratio of their speeds.
When two individuals run on a circular track starting from the same point in the same direction, they meet when the difference in the distance covered by them is an integer multiple of the track length. The point where they meet depends on the ratio of their speeds.
Let the speed of the faster runner (say, Munaf) be $v_f$ and the speed of the slower runner (say, Surya) be $v_s$. The problem states that the ratio of the speed of the faster boy to that of the slower one is $n : 1$. So, we have:
$$ \frac{v_f}{v_s} = \frac{n}{1} $$
Since the faster runner is mentioned, $v_f > v_s$, which means $n > 1$. Also, 'n' is a natural number.
When two runners start from the same point and run in the same direction on a circular track with speeds in the ratio $v_f : v_s = n : 1$, the number of distinct points on the track where they can meet is given by $|n - 1|$. Since $n$ is a natural number and $n > 1$, the number of distinct meeting points is $n - 1$.
The problem states that they meet at the same point on the track for the 31st time and the 43rd time. The meeting points on a circular track repeat in cycles. If the number of distinct meeting points is $P$, then the $(k)$-th meeting point is the same as the $(k + m \times P)$-th meeting point for any positive integer $m$.
In this case, the 31st meeting point is the same as the 43rd meeting point. This means that the difference between the meeting numbers, $43 - 31$, must be a multiple of the number of distinct meeting points.
The difference in meeting numbers is:
$$ 43 - 31 = 12 $$
This difference (12) must be a multiple of the number of distinct meeting points, which we found to be $(n - 1)$.
So, we can write:
$$ 12 = k \times (n - 1) $$
where $k$ is a positive integer.
This implies that $(n - 1)$ must be a divisor of 12.
Let's find the divisors of 12. The positive divisors of 12 are 1, 2, 3, 4, 6, and 12.
Since $(n - 1)$ must be a divisor of 12, the possible values for $(n - 1)$ are 1, 2, 3, 4, 6, or 12.
We can find the corresponding possible values for $n$ by adding 1 to each of these divisors:
| Possible value for $(n - 1)$ | Possible value for $n$ |
|---|---|
| 1 | $1 + 1 = 2$ |
| 2 | $2 + 1 = 3$ |
| 3 | $3 + 1 = 4$ |
| 4 | $4 + 1 = 5$ |
| 6 | $6 + 1 = 7$ |
| 12 | $12 + 1 = 13$ |
So, the possible values for $n$ are 2, 3, 4, 5, 7, and 13.
The given options for the value of $n$ are:
We need to find which of these options is NOT a possible value of $n$. Let's compare the given options with the list of possible values (2, 3, 4, 5, 7, 13):
Based on our analysis, for the 31st and 43rd meeting points to be the same, the value of $(n-1)$ must be a divisor of 12. This restricts the possible values of $n$. Out of the given options, 6 is the only value that does not appear in the list of possible values for $n$. Therefore, 6 is NOT a possible value of 'n'.
| Concept | Description (Same Direction) |
|---|---|
| Relative Speed | Difference between faster and slower speeds ($v_f - v_s$) |
| Time for 1st Meeting (not necessarily at start) | Track Length / Relative Speed |
| Ratio of Speeds ($v_f : v_s$) | $n : 1$ (simplest form, $n > 1$) |
| Number of Distinct Meeting Points | $n - 1$ |
| Meeting Point Repetition | $(k)$-th meeting point is same as $(k + m \times (n-1))$-th |
Understanding relative speed is crucial for circular track problems. When runners move in the same direction, the relative speed is the difference between their speeds. When they move in opposite directions, the relative speed is the sum of their speeds.
If runners start at the same point and run in opposite directions with a speed ratio of $n:1$, the number of distinct meeting points is $n+1$. If they start at different points, the analysis becomes slightly more complex but still relies on relative speed and the fraction of the track length between them.
The first time runners meet at the starting point when running in the same direction is after the faster runner has gained a full lap over the slower runner. This happens after a time equal to Track Length / (Relative Speed). Subsequent meetings at the starting point also occur at intervals of this time.
Two trains start from places A and B. respectively, and travel towards each other at the speeds of 60 km/h and 50 km/h. respectively. By the time they meet, the faster train has travelled 110 km more than the slower train. What is the distance between A and B?
A train can cross a tunnel of length 600 m in 54 seconds, and it can cross a 350 m long bridge in 36 seconds. Which of the following statements is/are correct?
(i) The speed of the train is 60 km/h.
(ii) The length of the train is 150 m
Raghu and Raman start together to walk a certain equal distance at a speed of 10 km/h and 8 km/h, respectively. Raghu arrives 30 minutes before Raman arrives. Find the distance between the start and the end point.
A and B started simultaneously and proceeded towards each other from places X and Y, respectively. After meeting each other at a certain point on the way, A and B took 3.2 hours and 1.8 hours, to reach Y and X, respectively. If the speed of B was 12 km/h, then the speed (in km/h) of A was:
Anil started his journey in the morning. Till 10 a.m., he covered \(\frac{1}{2}\) of his journey, and on the same day till 1 a.m., he covered \(\frac{4}{5}\) of his journey. At what time did he start his journey?