Modulus of elasticity of concrete, E is calculated using:
The modulus of elasticity, often denoted as E, is a fundamental material property that describes its stiffness. In simpler terms, it tells us how much a material will deform elastically under stress. For concrete, the modulus of elasticity is an important parameter used in structural analysis and design calculations, especially when determining deflections and deformations under load.
The modulus of elasticity of concrete is influenced by several factors, including:
For standard concrete used in design, codes often provide empirical formulas to estimate the short-term static modulus of elasticity based on the characteristic compressive strength. The characteristic compressive strength of concrete is denoted by \(f_{ck}\).
Based on common standards and practices in structural engineering, the short-term static modulus of elasticity (\(E\)) for concrete is widely calculated using the following formula:
\[\rm{E = 5000\sqrt{f_{ck}}}\]
where:
We are given several options for calculating the modulus of elasticity of concrete, E:
Comparing these options with the standard formula used for calculating the modulus of elasticity of concrete, we can see that Option 1 matches the widely accepted empirical relationship.
The modulus of elasticity of concrete, E, is calculated using the formula \( \rm{E = 5000\sqrt{f_{ck}}} \), where \( f_{ck} \) is the characteristic compressive strength of the concrete.
| Option | Formula | Correctness |
|---|---|---|
| 1 | \( \rm{E = 5000\sqrt{f_{ck}}} \) | Correct |
| 2 | \( \rm{E = 500\sqrt{f_{ck}}} \) | Incorrect |
| 3 | \( \rm{E = 50\sqrt{f_{ck}}} \) | Incorrect |
| 4 | \( \rm{E = 5\sqrt{f_{ck}}} \) | Incorrect |
| Concept | Description | Formula |
|---|---|---|
| Modulus of Elasticity (E) | Measure of concrete stiffness, resistance to elastic deformation under stress. | \( \rm{E = 5000\sqrt{f_{ck}}} \) (Short-term static) |
| Characteristic Compressive Strength (\(f_{ck}\)) | Concrete cube strength at 28 days, used as a parameter in the formula. | - |
While \( \rm{E = 5000\sqrt{f_{ck}}} \) gives the short-term static modulus of elasticity, the actual modulus can vary. Factors like long-term loads (creep) and dynamic loads can affect the effective modulus. Design codes often provide adjustments or different values for specific applications.
Other important properties of concrete include:
Understanding these properties is crucial for the safe and efficient design of concrete structures.
In the following table, the left column contains the names of standard graph algorithms and the right column contains the time complexities of the algorithms. Here, n and m are number of vertices and edges, respectively. Match each algorithm with its time complexity.
| List I | List II | ||
| Standard graph algorithms | Time complexities | ||
| A. | Bellman‐Ford algorithm | I. | O(m*log n) |
| B. | Kruskal’s algorithm | II. | O(n 3) |
| C. | Floyd‐Warshall algorithm | III. | O(n*m) |
| D. | Topological sorting | IV. | O(n + m) |
Choose the correct answer from the options given below :
How many cards must be selected from a standard deck of 52 cards to guarantee that at least three hearts are present among them?
Match List 1 with List 2 and choose the correct answer from the code given below:
List I (Graph Algorithm) | List II (Time Complexity) |
a) Dijkstra’s algorithm | i) Θ(E log E) |
b) Kruskal’s algorithm | ii) Θ(V 3) |
c) Floyd-Warshall algorithm | iii) Θ(V 2) |
d) Topological sorting | iv) Θ(V + E) |
Where V and E are the number of vertices and edges in graph respectively.
The solution of recurrence relation: T(n)=2T(sqrt(n)) + lg(n) is
In how many types can R.C.C. be classified into?