The concentration of a substance in solution can be determined using the Beer-Lambert Law when its absorbance is known. The law relates absorbance ($A$) to the molar extinction coefficient ($\epsilon$), concentration ($c$), and path length ($l$).
The Beer-Lambert Law is stated as:
$ A = \epsilon \times c \times l $
To find the concentration ($c$), we can rearrange the formula:
$ c = \frac{A}{\epsilon \times l} $
Given values are:
Substitute these values into the rearranged formula:
$ c = \frac{0.31}{6200 \, M^{-1} cm^{-1} \times 1 \, cm} $
$ c = \frac{0.31}{6200} \, M $
Performing the calculation:
$ c \approx 0.00005 \, M $
The question asks for the concentration in micromolar ($\mu M$). To convert from Molar ($M$) to micromolar ($\mu M$), multiply by $10^6$:
$ c \approx 0.00005 \times 10^6 \, \mu M $
$ c \approx 50 \, \mu M $
The concentration of NADH in the solution is approximately 50 $\mu M$. Correct to the nearest integer, the value is 50.