Mayank’s house faces South. He leaves from the back gate of his house and walks 18 m. Then he turns right and walks 28 m. Then he turns right and walks 35 m. Then he turns left and walks 12 m. He then turns left and walks 17 m. In which direction and how many meters away is he from the original position?
40 meters East
This question asks us to find the final position of a person, Mayank, relative to his starting point after a series of movements in different directions. To solve this type of problem, we can visualize the movements on a coordinate plane or simply track the net displacement in the East-West and North-South directions.
First, let's establish the starting point and direction. Mayank's house faces South, which means the back gate faces the opposite direction, North. He leaves from the back gate, so his initial movement is towards the North.
Let's break down Mayank's journey step by step:
We can track the movements in terms of North (+ve Y-axis), South (-ve Y-axis), East (+ve X-axis), and West (-ve X-axis). Let's assume the starting point is the origin (0,0).
| Step | Direction | Distance (m) | X Change | Y Change | Current Position (X, Y) |
|---|---|---|---|---|---|
| Start | - | - | 0 | 0 | (0, 0) |
| 1 | North | 18 | 0 | +18 | (0, 18) |
| 2 | Right (East) | 28 | +28 | 0 | (0+28, 18+0) = (28, 18) |
| 3 | Right (South) | 35 | 0 | -35 | (28+0, 18-35) = (28, -17) |
| 4 | Left (East) | 12 | +12 | 0 | (28+12, -17+0) = (40, -17) |
| 5 | Left (North) | 17 | 0 | +17 | (40+0, -17+17) = (40, 0) |
Alternatively, we can calculate the net displacement in the East-West and North-South directions directly:
The net displacement is 0 m in the North-South direction and +40 m in the East-West direction. A positive value for East-West means he is 40 meters towards the East from the starting point. A net displacement of 0 in North-South means he is neither North nor South of the starting point.
His final position is effectively 40 meters East and 0 meters North/South of his original position.
The distance from the original position is the magnitude of the displacement vector, which in this case is simply the Eastward displacement since the North-South displacement is zero.
Distance $= \sqrt{(\text{Net East-West})^2 + (\text{Net North-South})^2}$
Distance $= \sqrt{(40)^2 + (0)^2}$
Distance $= \sqrt{1600 + 0}$
Distance $= \sqrt{1600}$
Distance $= 40$ meters.
Since the entire displacement is towards the East (+ve X-axis), his final direction from the original position is East.
After all the movements, Mayank is 40 meters away from his original position, and he is in the East direction relative to that position.
| Concept | Description |
|---|---|
| Cardinal Directions | North, South, East, West. Often mapped to Y+, Y-, X+, X-. |
| Turning Right/Left | Relative to the current direction of movement. If facing North, Right is East, Left is West. If facing East, Right is South, Left is North, etc. |
| Displacement | The shortest distance between the initial and final points, including direction. It's a vector quantity. |
| Distance Traveled | The total length of the path covered. This is a scalar quantity and different from displacement. |
| Original Position | The starting point, often considered the origin (0,0). |
| Final Position | The end point after all movements. |
Direction and distance questions often involve tracking movements on a 2D plane. It's helpful to:
Remember that "distance from the original position" usually refers to the straight-line distance (magnitude of displacement) between the start and end points.
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