Maximum velocity condition in a flow-through circular channel section is:
H = 0.81d; Area of flow = R2/2(2θ - sin 2θ)
In open channel flow, the velocity of water varies depending on the depth of flow, especially in non-rectangular sections like a circular channel. For a given discharge, the maximum velocity does not necessarily occur when the channel is full. It occurs at a specific partial depth of flow.
The velocity in an open channel is often estimated using empirical formulas like Manning's equation or Chezy's equation. These equations relate velocity (\(V\)) to the hydraulic radius (\(R_h\)) and the slope (\(S\)).
Manning's Equation: \(V = \frac{1}{n} R_h^{2/3} S^{1/2}\)
Where:
For a circular channel with a fixed slope (\(S\)) and roughness (\(n\)), the velocity \(V\) is maximum when the hydraulic radius \(R_h\) is maximum. The hydraulic radius \(R_h = A/P\) changes with the depth of flow.
Calculations show that the hydraulic radius, and thus the velocity, is maximized in a circular channel when the depth of flow (\(H\)) is approximately 0.81 times the diameter (\(d\)) of the channel.
This critical depth for maximum velocity is given by:
\(H \approx 0.81d\)
Or, in terms of radius (\(R = d/2\)):
\(H \approx 0.81 \times 2R = 1.62R\)
For a partially filled circular channel, the area of flow is the area of the circular segment below the water surface. If \(R\) is the radius of the pipe and \(2\theta\) is the angle (in radians) subtended by the water surface at the center of the circle, the area of flow (\(A\)) is given by:
\(A = \text{Area of sector} - \text{Area of triangle}\)
\(A = \frac{1}{2}R^2 (2\theta) - \frac{1}{2}R^2 \sin(2\theta)\)
\(A = R^2 \theta - \frac{1}{2}R^2 \sin(2\theta)\)
\(A = \frac{R^2}{2}(2\theta - \sin 2\theta)\)
This formula for the area of flow is standard for a circular segment where \(2\theta\) is the central angle subtended by the water surface chord.
The condition for maximum velocity requires the depth of flow to be \(H \approx 0.81d\). The formula for the area of flow for a partial circle is \(A = \frac{R^2}{2}(2\theta - \sin 2\theta)\).
Comparing this with the given options, the condition that matches the established depth for maximum velocity and the standard area formula is:
Therefore, the maximum velocity condition in a flow-through circular channel section is characterized by these two parameters.
| Parameter | Condition for Maximum Velocity |
|---|---|
| Depth of Flow (H) | \(\approx 0.81d\) (where \(d\) is the diameter) |
| Area of Flow (A) | \(\frac{R^2}{2}(2\theta - \sin 2\theta)\) (where \(R\) is radius, \(2\theta\) is central angle) |
The condition for maximum velocity in a circular channel occurs at a specific depth, which maximizes the hydraulic radius. This depth is approximately 0.81 times the channel diameter, and the area of flow at this depth is calculated using the formula for a circular segment based on the central angle subtended by the water surface.
| Condition | Depth (H) | Area (A) | Wetted Perimeter (P) | Notes |
|---|---|---|---|---|
| Maximum Velocity | \(\approx 0.81d\) | \(\frac{R^2}{2}(2\theta - \sin 2\theta)\) | \(R(2\theta)\) | Maximizes Hydraulic Radius (\(R_h = A/P\)) |
| Maximum Discharge | \(\approx 0.95d\) | \(R^2(\theta - \frac{1}{2}\sin 2\theta)\) at this depth | \(R(2\theta)\) at this depth | Maximizes \(A \cdot R_h^{2/3}\) |
| Full Pipe | \(d\) | \(\pi R^2\) | \(\pi d\) or \(2\pi R\) | Not max velocity or max discharge |
Open channel flow refers to the flow of liquid in a conduit with a free surface exposed to the atmosphere. Circular channels, such as storm sewers and culverts, are common examples.
Understanding these conditions is crucial for the efficient design and analysis of circular drainage systems.
Which of the following statements is NOT correct?
The average daily flow of wastewater generated from residential, commercial, and industrial sources, specifically excluding any contribution from rainfall or stormwater, is commonly referred to as:
As per NBO, the gradient required to generate self-cleansing velocity for a 100 mm Φ sewer is _____.
Which of the following problems does proper sewer ventilation help to mitigate?
Maximum discharge through a circular channel takes place when depth of flow is equal to