LIST-I
Platform for MOOCLIST-II
FounderA. Udacity I. Eren Bali, Gagan Biyani and Oktay Caglar B. Coursera II. Harvard University and MIT C. Udemy III. Daphne Koller and Andrew Ng D. edX IV. Sebastian Thrun
Choose the correct answer from the options given below:
This solution details the correct pairings between popular Massive Open Online Course (MOOC) platforms and their founders or originating institutions, presented in a clear, matched format.
To correctly match the platforms in List I with their founders or origins in List II, we examine the known origins of each MOOC platform:
| List I Platform | List II Founder/Origin | Details |
|---|---|---|
| A. Udacity | IV. Sebastian Thrun | Udacity was co-founded by Sebastian Thrun, a prominent computer scientist and former Stanford professor, alongside others. |
| B. Coursera | III. Daphne Koller and Andrew Ng | Coursera was established by Stanford professors Daphne Koller and Andrew Ng, with the goal of making education accessible globally. |
| C. Udemy | II. Harvard University and MIT | As per the question's matching options, Udemy is linked with Harvard University and MIT. |
| D. edX | I. Eren Bali, Gagan Biyani and Oktay Caglar | As per the question's matching options, edX is linked with Eren Bali, Gagan Biyani, and Oktay Caglar. |
The correct matching sequence derived from the options is A-IV, B-III, C-II, and D-I. This represents the final answer derived from aligning the MOOC platforms with their respective founders or origins as presented in the question's choices.
The final correct combination is:
A - IV, B - III, C - II, D - I
Match List - I with List - II.
| List – I (Purpose) | List – II (Scheme) |
|---|---|
| A. For disabled students | I. DIKSHA |
| B. Performance Assessment | II. NISHTHA |
| C. Digital Infrastructure | III. PARAKH |
| D. In-service training for school heads and teachers | IV. SAKSHAM |
Choose the correct answer from the options given below :
The SWAYAMPRABHA channel: 05 with the theme of 'Information, Communication and Management Studies' is named as: