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Question

Match the followings

I. Ratio of long chord to tangent length of a simple circular curve of radius R and deflection angle Δ° 

II. Ratio of long chord to the length of simple circular curve of radius R and deflection angle Δ° 
A. sin (Δ°/2)

B. cos (Δ°/2)

C. 2cos(Δ°/2)

D. 360° sin (Δ°/2)/Δπ 

E. 360° cos (Δ°/2)/Δπ 

The correct answer is I - C, II - D

Understanding Simple Circular Curve Ratios

This solution explains how to match the given ratios related to a simple circular curve with its defining parameters: radius (R) and deflection angle (Δ°).

Matching Item I: Ratio of Long Chord to Tangent Length

First, let's recall the standard formulas for the long chord (LC) and the tangent length (T) of a simple circular curve:

  • Long Chord (LC): The straight line connecting the beginning and end points of the curve. Its formula is given by: $$ LC = 2R \sin\left(\frac{\Delta\textdegree}{2}\right) $$
  • Tangent Length (T): The distance from the point of intersection (PI) of the tangents to the tangent point (either back tangent or forward tangent). Its formula is: $$ T = R \tan\left(\frac{\Delta\textdegree}{2}\right) $$

Now, we calculate the ratio of the long chord to the tangent length:

$$ \text{Ratio (I)} = \frac{LC}{T} = \frac{2R \sin\left(\frac{\Delta\textdegree}{2}\right)}{R \tan\left(\frac{\Delta\textdegree}{2}\right)} $$

We know that $ \tan(x) = \frac{\sin(x)}{\cos(x)} $. Substituting this into the ratio:

$$ \text{Ratio (I)} = \frac{2R \sin\left(\frac{\Delta\textdegree}{2}\right)}{R \frac{\sin\left(\frac{\Delta\textdegree}{2}\right)}{\cos\left(\frac{\Delta\textdegree}{2}\right)}} $$

Simplifying the expression by canceling out common terms ($R$ and $ \sin\left(\frac{\Delta\textdegree}{2}\right) $):

$$ \text{Ratio (I)} = \frac{2}{\frac{1}{\cos\left(\frac{\Delta\textdegree}{2}\right)}} = 2 \cos\left(\frac{\Delta\textdegree}{2}\right) $$

This result matches option C.

Matching Item II: Ratio of Long Chord to Length of Curve

Next, we need the formula for the length of the simple circular curve (L).

  • Length of Curve (L): The actual length along the arc of the curve. For a deflection angle Δ° and radius R, the length is calculated as: $$ L = R \times \left(\frac{\Delta\textdegree}{180\textdegree} \times \pi \right) $$ This formula converts the deflection angle from degrees to radians ($ \theta_{rad} = \Delta\textdegree \times \frac{\pi}{180\textdegree} $) and then uses the arc length formula $ L = R \theta_{rad} $.

Now, we calculate the ratio of the long chord to the length of the curve:

$$ \text{Ratio (II)} = \frac{LC}{L} = \frac{2R \sin\left(\frac{\Delta\textdegree}{2}\right)}{R \times \left(\frac{\Delta\textdegree}{180\textdegree} \times \pi \right)} $$

Simplifying the expression:

$$ \text{Ratio (II)} = \frac{2 \sin\left(\frac{\Delta\textdegree}{2}\right)}{\frac{\Delta\textdegree \pi}{180\textdegree}} $$

To get the numerator factor of 360, we multiply the numerator and denominator by 180:

$$ \text{Ratio (II)} = \frac{2 \times 180\textdegree \sin\left(\frac{\Delta\textdegree}{2}\right)}{\Delta\textdegree \pi} = \frac{360\textdegree \sin\left(\frac{\Delta\textdegree}{2}\right)}{\Delta\textdegree \pi} $$

This result matches option D.

Conclusion

Based on the calculations:

  • Item I (Ratio of long chord to tangent length) matches C. $ 2 \cos\left(\frac{\Delta\textdegree}{2}\right) $.
  • Item II (Ratio of long chord to the length of the simple circular curve) matches D. $ \frac{360\textdegree \sin\left(\frac{\Delta\textdegree}{2}\right)}{\Delta\textdegree \pi} $.

Therefore, the correct matching is I - C, II - D.

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Important Questions from Curves

  1. The radius of a simple circular curve is 300m and the length of its specified chord is 20 m, The degree of the curve is:

  2. Which of the following methods is NOT commonly used in setting out circular curves?

  3. A curve which consists of two circular arcs of same and different radii having their centres to the different sides of the common tangent is called:

  4. The tangent length for a simple curve is 10 m. the chainage of point of intersection is 344.465 m. The chainage of starting point of curve is:

  5. In India, the standard chord length used in curves is:

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