Match List I with List II List – I List – II JFET - Bias Characteristic Equation A. Self - bias I. \(\rm I_D = \frac{V_{SS}-V_{GS}}{R_S}\) B. Voltage – divider bias II. \(\rm I_D = \frac{V_{EE}-V_{BE}}{R_E}\) C. Source bias III. V GS = -I DR S D. Current – source bias IV. \(\rm I_D = \frac{V_{G}-V_{GS}}{R_S}\) Choose the correct answer from the options given below:
A ‐ III, B ‐ IV, C ‐ I, D ‐ II
JFET biasing is essential to establish a stable DC operating point (Q-point) for the JFET amplifier. The Q-point determines the quiescent drain current (\(\rm I_D\)) and gate-source voltage (\(\rm V_{GS}\)) when no AC signal is applied. Different biasing methods are used to achieve this, and each method leads to a specific relationship between the circuit voltages, resistances, and the JFET parameters.
Let's analyze each JFET bias method listed and derive or identify its characteristic equation from the given options.
In a self-bias circuit, a resistor (\(\rm R_S\)) is connected between the source terminal and ground. The gate is typically connected to ground through a resistor (\(\rm R_G\)), which is very large and carries negligible current, making the gate voltage (\(\rm V_G\)) approximately 0V. The drain current (\(\rm I_D\)) flows through \(\rm R_S\), creating a voltage drop across it (\(\rm V_S = I_D R_S\)). The gate-source voltage (\(\rm V_{GS}\)) is given by \(\rm V_{GS} = V_G - V_S\). Since \(\rm V_G \approx 0\), we get \(\rm V_{GS} = 0 - I_D R_S = -I_D R_S\). This equation directly relates \(\rm V_{GS}\) and \(\rm I_D\) for a given \(\rm R_S\).
This matches with List II equation III: \(\rm V_{GS} = -I_D R_S\).
This method uses a voltage divider network (usually two resistors \(\rm R_1\) and \(\rm R_2\)) connected to the gate to establish a fixed gate voltage (\(\rm V_G = V_{DD} \frac{R_2}{R_1+R_2}\)). A source resistor (\(\rm R_S\)) is also used. The source voltage (\(\rm V_S\)) is related to the drain current by \(\rm V_S = I_D R_S\). The gate-source voltage is \(\rm V_{GS} = V_G - V_S = V_G - I_D R_S\). Rearranging this equation to express \(\rm I_D\) in terms of \(\rm V_G\), \(\rm V_{GS}\), and \(\rm R_S\): \(\rm I_D R_S = V_G - V_{GS}\), which gives \(\rm I_D = \frac{V_{G}-V_{GS}}{R_S}\). This equation represents the load line for the voltage-divider bias circuit on the \(\rm I_D\) vs \(\rm V_{GS}\) characteristic curve.
This matches with List II equation IV: \(\rm I_D = \frac{V_{G}-V_{GS}}{R_S}\).
In a source bias circuit, the gate is usually grounded (\(\rm V_G = 0\)), and the source resistor (\(\rm R_S\)) is connected to a negative supply voltage (\(\rm -V_{SS}\)). The drain current (\(\rm I_D\)) flows through \(\rm R_S\). The voltage at the source terminal (\(\rm V_S\)) and the negative supply voltage \(\rm -V_{SS}\) relate to the voltage drop across \(\rm R_S\) by \(\rm V_S - (-V_{SS}) = I_D R_S\), or \(\rm V_S + V_{SS} = I_D R_S\). The gate-source voltage is \(\rm V_{GS} = V_G - V_S = 0 - V_S = -V_S\), so \(\rm V_S = -V_{GS}\). Substituting this into the previous equation: \(\rm -V_{GS} + V_{SS} = I_D R_S\). Rearranging to solve for \(\rm I_D\): \(\rm I_D R_S = V_{SS} - V_{GS}\), which gives \(\rm I_D = \frac{V_{SS}-V_{GS}}{R_S}\).
This matches with List II equation I: \(\rm I_D = \frac{V_{SS}-V_{GS}}{R_S}\).
This biasing method uses a constant current source connected to the source terminal of the JFET. This current source is often implemented using a BJT or another JFET. If a BJT is used as the current source, its collector current (which is approximately equal to the emitter current \(\rm I_E\)) sets the JFET's drain current (\(\rm I_D \approx I_E\)). A common BJT current source configuration uses an emitter resistor \(\rm R_E\) connected to a negative supply voltage \(\rm V_{EE}\). The base is typically at a fixed voltage (e.g., grounded or biased by a voltage divider). Assuming the base is grounded (\(\rm V_B = 0\)) and the emitter is at voltage \(\rm V_E\), the voltage across \(\rm R_E\) is \(\rm V_E - V_{EE}\). The emitter current is \(\rm I_E = \frac{V_E - V_{EE}}{R_E}\). The base-emitter voltage is \(\rm V_{BE} = V_B - V_E = 0 - V_E = -V_E\), so \(\rm V_E = -V_{BE}\). Substituting this into the \(\rm I_E\) equation gives \(\rm I_E = \frac{-V_{BE} - V_{EE}}{R_E}\). However, List II equation II is \(\rm I_D = \frac{V_{EE}-V_{BE}}{R_E}\). This equation corresponds to a common BJT current source calculation where \(V_{BE}\) is treated as approximately constant (e.g., 0.7V for silicon) and the base voltage is fixed, often to ground, while \(\rm R_E\) is connected to the negative supply \(V_{EE}\). The voltage at the emitter will be \(\approx -V_{BE}\). Then \(\rm I_E = \frac{-V_{BE} - V_{EE}}{R_E} = \frac{-(V_{BE} + V_{EE})}{R_E}\). There seems to be a sign difference or convention issue in option II compared to the standard derivation from a BJT current source where \(V_{EE}\) is a negative value. However, interpreting \(\rm V_{EE}\) as the magnitude of the negative supply (so the supply is at \(-V_{EE}\)) and the base is at 0V, the emitter voltage is approximately \(-V_{BE}\) (relative to ground). The voltage across \(\rm R_E\) is \(-V_{BE} - (-V_{EE}) = V_{EE} - V_{BE}\). Thus, \(\rm I_E = \frac{V_{EE}-V_{BE}}{R_E}\). Since \(\rm I_D \approx I_E\), we get \(\rm I_D \approx \frac{V_{EE}-V_{BE}}{R_E}\).
This matches with List II equation II: \(\rm I_D = \frac{V_{EE}-V_{BE}}{R_E}\).
Based on the analysis:
The correct matching is A - III, B - IV, C - I, D - II.
| List I (JFET Bias) | List II (Characteristic Equation) | Matching |
|---|---|---|
| A. Self - bias | I. \(\rm I_D = \frac{V_{SS}-V_{GS}}{R_S}\) | A ‐ III |
| B. Voltage – divider bias | II. \(\rm I_D = \frac{V_{EE}-V_{BE}}{R_E}\) | B ‐ IV |
| C. Source bias | III. \(\rm V_{GS} = -I_D R_S\) | C ‐ I |
| D. Current – source bias | IV. \(\rm I_D = \frac{V_{G}-V_{GS}}{R_S}\) | D ‐ II |
Here is a quick review of the characteristic equations for these JFET bias types:
| JFET Bias Type | Characteristic Equation | Notes |
|---|---|---|
| Self-bias | \(\rm V_{GS} = -I_D R_S\) | Relates \(\rm V_{GS}\) and \(\rm I_D\). Gate voltage is typically 0V. |
| Voltage-divider bias | \(\rm I_D = \frac{V_{G}-V_{GS}}{R_S}\) | \(\rm V_G\) is fixed by the voltage divider. This is a load line equation. |
| Source bias | \(\rm I_D = \frac{V_{SS}-V_{GS}}{R_S}\) | Gate voltage is typically 0V. \(\rm -V_{SS}\) is the negative supply connected to \(\rm R_S\). |
| Current-source bias | \(\rm I_D \approx \frac{V_{EE}-V_{BE}}{R_E}\) | Assumes BJT current source implementation, where this is the BJT's emitter current equation. |
JFETs (Junction Field-Effect Transistors) require biasing to set the DC operating point within the pinch-off or saturation region (for common amplifier configurations). Proper biasing ensures that the transistor operates linearly for AC signals without distortion.
\(\rm I_D = I_{DSS}\left(1 - \frac{V_{GS}}{V_P}\right)^2\)
where \(\rm I_{DSS}\) is the drain current at \(\rm V_{GS}=0\) and \(\rm V_P\) is the pinch-off voltage (or \(\rm V_{GS(off)}\)). Biasing circuits provide a second equation (the load line) that, when solved simultaneously with Shockley's equation, determines the Q-point.
Understanding the characteristic equation for each bias circuit is crucial for calculating the Q-point and analyzing the circuit's behavior.
A JFET has high input impedance because-
The transconductance g mof a JFET is equal to:
\(\frac{ I _{ DSS }}{ V _{ P }}\left(1-\frac{ V _{ GS }}{ V _{ P }}\right)\)
The CMOS inverter can be used as an amplifier when:
In JFET, the Pinch‐off Voltage can be defined as:
In JFET, the current density in the x-direction is:
A. σ(x)E x
B. qN DμE x
C. \(\rm \frac{q}{2 \in_s}N_D\mu\)
D. \(\rm \frac{N_D\mu}{2 \in_s}\)
Choose the correct answer from the options given below: