Match List I with List II: Choose the correct answer from the options given below:List I List II (A) Shannon's theorem (I) Capacity of Gaussian Noise channel (B) Shannon-Hartley theorem (II) Rate of Information (C) Bayes theorem (III) Energy of a signal (D) Parseval's theorem (IV) Conditional probabilities
(A) - (II), (B) - (I), (C) - (IV), (D) - (III)
This question asks us to match fundamental theorems and concepts from various fields of engineering and mathematics to their associated definitions or applications. Let's analyze each pairing based on standard definitions and principles.
\(C = B \log_2(1 + S/N)\)
Where \(C\) is the channel capacity in bits per second, \(B\) is the bandwidth of the channel in hertz, and \(S/N\) is the signal-to-noise power ratio.
\(P(A|B) = \frac{P(B|A) P(A)}{P(B)}\)
Here, \(P(A|B)\) is the posterior probability of A given B, \(P(B|A)\) is the likelihood of B given A, \(P(A)\) is the prior probability of A, and \(P(B)\) is the probability of B. This theorem is directly about relating and calculating conditional probabilities. List II option "(IV) Conditional probabilities" is the direct domain of Bayes theorem.
\(E = \int_{-\infty}^{\infty} |x(t)|^2 dt = \frac{1}{2\pi} \int_{-\infty}^{\infty} |X(\omega)|^2 d\omega\)
For a discrete-time signal \(x[n]\) with Discrete-Time Fourier Transform \(X(e^{j\omega})\):
\(E = \sum_{n=-\infty}^{\infty} |x[n]|^2 = \frac{1}{2\pi} \int_{-\pi}^{\pi} |X(e^{j\omega})|^2 d\omega\)
Parseval's theorem is explicitly concerned with the energy of a signal, making List II option "(III) Energy of a signal" the correct match.
Based on the analysis:
Let's put this into a table format for clarity.
| List I | List II | Matching Concept |
|---|---|---|
| (A) Shannon's theorem | (II) Rate of Information | Deals with the minimum bits per symbol for source encoding. |
| (B) Shannon-Hartley theorem | (I) Capacity of Gaussian Noise channel | Calculates the maximum reliable data rate over a noisy channel. |
| (C) Bayes theorem | (IV) Conditional probabilities | Provides a way to update probabilities based on evidence. |
| (D) Parseval's theorem | (III) Energy of a signal | Relates signal energy in time and frequency domains. |
Comparing our derived matchings with the given options, the correct option corresponds to: (A) - (II), (B) - (I), (C) - (IV), (D) - (III).
| Theorem/Concept | Field | Primary Application/Definition |
|---|---|---|
| Shannon's Theorem (Source Coding) | Information Theory | Minimum Rate of Information / Data Compression Limit (Entropy) |
| Shannon-Hartley Theorem | Information Theory / Communications | Channel Capacity (Max reliable rate) for AWGN channels |
| Bayes Theorem | Probability Theory / Statistics | Updating Conditional Probabilities / Bayesian Inference |
| Parseval's Theorem | Signal Processing / Fourier Analysis | Energy Conservation between Time and Frequency Domains |
These theorems are cornerstones in their respective fields.
Noise factor of a system is defined as:
The information capacity (bits/sec) of a channel with bandwidth C and transmission time T is given by
The capacity of band-limited additive white Gaussian Noise (AWGN) channel is given by \(C = W{\log _2}\left[ {1 + \frac{P}{{{\sigma ^2}w}}} \right]\) bits per second (bps), where W is the channel Bandwidth, P is the average power received and σ2 is the one-sided power spectral density of the AWGN.
For a fixed \(\frac{P}{{{\sigma ^2}}} = 1000\), the channel capacity (in kbps) with infinite Bandwidth (W → ∞) is approximately
Consider an additive white Gaussian noise (AWGN) channel with bandwidth W and noise power spectral density $\frac{N_0}{2}$. Let $P_{av}$ denote the average transmit power constraint. Which one of the following plots illustrates the dependence of the channel capacity C on the bandwidth W (keeping $P_{av}$ and $N_0$ fixed)?
A voice-grade AWGN (additive white Gaussian noise) telephone channel has a bandwidth of 4.0 kHz and two-sided noise power spectral density $ \frac{\eta}{2} = 2.5\times10^{-5} $ Watt per Hz. If information at the rate of 52 kbps is to be transmitted over this channel with arbitrarily small bit error rate, then the minimum bit-energy $E_b$ (in mJ/bit) necessary is ____________