Match List I with List II : List – I (Limits) List – II (% of area in NPC) (a) –2 sigma to –1 sigma (I) 95.44 (b) 0 to + 2 sigma (II) 13.59 (c) –1 to +2 sigma (III) 72.67 (d) –2 sigma to +2 sigma (IV) 81.85 (V) 47.72
Choose the correct answer from the options given below:
(A) – (II), (B) – (V), (C) – (IV), (D) – (I)
The question asks us to match specific ranges defined by standard deviations ($\sigma$) on a Normal Probability Curve (NPC) with the percentage of the total area under the curve that falls within those ranges. The Normal Probability Curve, also known as the Gaussian distribution or bell curve, is symmetrical around its mean, which corresponds to the 0 standard deviation mark.
The total area under the NPC is 100%. The percentage of area between the mean (0) and a certain number of standard deviations is a key property. Due to symmetry, the area from 0 to $+z\sigma$ is the same as the area from 0 to $-z\sigma$.
Here are some common areas from the mean (0):
Let's calculate the percentage of area for each limit given in List I based on these properties:
This range is entirely to the left of the mean. We can find this area by taking the area from –2$\sigma$ to 0 and subtracting the area from –1$\sigma$ to 0.
Area (–2$\sigma$ to –1$\sigma$) = Area (–2$\sigma$ to 0) – Area (–1$\sigma$ to 0)
Area (–2$\sigma$ to –1$\sigma$) = $47.72\% - 34.13\% = 13.59\%$.
This matches option (II) in List II.
This is a standard range from the mean to $+2\sigma$.
Area (0 to +2$\sigma$) = $47.72\%$.
This matches option (V) in List II.
This range spans across the mean. We can find this area by adding the area from –1$\sigma$ to 0 and the area from 0 to +2$\sigma$.
Area (–1$\sigma$ to +2$\sigma$) = Area (–1$\sigma$ to 0) + Area (0 to +2$\sigma$)
Area (–1$\sigma$ to +2$\sigma$) = $34.13\% + 47.72\% = 81.85\%$.
This matches option (IV) in List II.
This range is symmetrical around the mean. We can find this area by taking twice the area from 0 to +2$\sigma$ (or 0 to –2$\sigma$).
Area (0 to +2$\sigma$) = $47.72\%$.
Area (–2$\sigma$ to +2$\sigma$) = $2 \times \text{Area (0 to +2}\sigma\text{)}$
Area (–2$\sigma$ to +2$\sigma$) = $2 \times 47.72\% = 95.44\%$.
This matches option (I) in List II.
Based on the calculations, the correct matching is:
| List I (Limits) | Calculated Area (% in NPC) | List II (% of area in NPC) | Matching |
|---|---|---|---|
| (a) –2$\sigma$ to –1$\sigma$ | $13.59\%$ | (II) $13.59\%$ | (a) - (II) |
| (b) 0 to +2$\sigma$ | $47.72\%$ | (V) $47.72\%$ | (b) - (V) |
| (c) –1$\sigma$ to +2$\sigma$ | $81.85\%$ | (IV) $81.85\%$ | (c) - (IV) |
| (d) –2$\sigma$ to +2$\sigma$ | $95.44\%$ | (I) $95.44\%$ | (d) - (I) |
The correct matching is (a)-(II), (b)-(V), (c)-(IV), (d)-(I).
| Range (Standard Deviations from Mean) | Approximate % of Area | Interpretation |
|---|---|---|
| Within $\pm 1\sigma$ (from –1$\sigma$ to +1$\sigma$) | $68.26\%$ | About two-thirds of the data falls within one standard deviation of the mean. |
| Within $\pm 2\sigma$ (from –2$\sigma$ to +2$\sigma$) | $95.44\%$ | About 95% of the data falls within two standard deviations of the mean. This is the range (d) from the question. |
| Within $\pm 3\sigma$ (from –3$\sigma$ to +3$\sigma$) | $99.72\%$ | Almost all data falls within three standard deviations of the mean. |
| 0 to +1$\sigma$ or 0 to –1$\sigma$ | $34.13\%$ | Area from the mean to one standard deviation. |
| 0 to +2$\sigma$ or 0 to –2$\sigma$ | $47.72\%$ | Area from the mean to two standard deviations. This is the range (b) from the question (specifically 0 to +2$\sigma$). |
| 0 to +3$\sigma$ or 0 to –3$\sigma$ | $49.86\%$ | Area from the mean to three standard deviations. |
| –2$\sigma$ to –1$\sigma$ | $13.59\%$ | Area between –2$\sigma$ and –1$\sigma$. This is the range (a) from the question. |
| –1$\sigma$ to +2$\sigma$ | $81.85\%$ | Area between –1$\sigma$ and +2$\sigma$. This is the range (c) from the question. |
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