Let A be the set {1, 2, 3, 4}. Which ordered pairs are in the relation R = {(a, b); a divides b}?
To determine the relation R, we need to find all ordered pairs $(a, b)$ such that $a$ and $b$ are elements of the set A = $\{1, 2, 3, 4\}$, and $a$ divides $b$. The condition "a divides b" means that when $b$ is divided by $a$, the remainder is zero. We will systematically check each element of A as $a$ and then as $b$ to form the ordered pairs.
The given set is A = $\{1, 2, 3, 4\}$.
The relation R is defined as R = $\{(a, b); a \text{ divides } b\}$, where $a \in \text{A}$ and $b \in \text{A}$.
Let's find all the ordered pairs $(a, b)$ that satisfy this condition.
We will go through each element $a$ in set A and find all elements $b$ in set A for which $a$ divides $b$.
Pairs from $a=1$: $(1, 1), (1, 2), (1, 3), (1, 4)$.
Pairs from $a=2$: $(2, 2), (2, 4)$.
Pairs from $a=3$: $(3, 3)$.
Pairs from $a=4$: $(4, 4)$.
Combining all the ordered pairs found above, the relation R is:
$$ \text{R} = \{(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (2, 4), (3, 3), (4, 4)\} $$Let's compare this derived set R with the given options:
| Option | Relation Set | Matches Derived R? | Reason (if No) |
|---|---|---|---|
| 1 | $\{(1, 1), (1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 3), (4, 4)\}$ | No | Includes $(2, 3)$, but $2$ does not divide $3$. |
| 2 | $\{(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (2, 3), (3, 1), (4, 4)\}$ | No | Includes $(2, 3)$ (false) and $(3, 1)$ (false). |
| 3 | $\{(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (2, 4), (3, 3), (4, 4)\}$ | Yes | Exactly matches our derived set R. |
| 4 | $\{(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (2, 3), (3, 3), (4, 4)\}$ | No | Includes $(2, 3)$, but $2$ does not divide $3$. |
Based on the comparison, Option 3 is the correct set of ordered pairs for the relation R where $a$ divides $b$.
A set S contains (2n + 1) elements. There are 4096 subsets of S which contain at most n elements. What is n equal to?
Let A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Then the number of subsets of A containing exactly two elements is
If A = { x : x is a multiple of 3} and B = (x : x is a multiple of 4} and C = {x : x is a multiple of 12}, then which one of the following is a null set?
Let S be a set of all distinct numbers of the form \(\frac{{\rm{p}}}{{\rm{q}}}\) , where p, q ∈ {1, 2, 3, 4, 5, 6}. What is the the cardinality of the set S?
If A and B are two sets containing 2 elements and 4 elements respectively, then number of subsets of A × B having 3 or more elements is :