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Question

Let A be {I, m, n}. Let the relation R be {}. Which of the following statements about R is true?

The correct answer is R is not reflexive, is symmetric, and is transitive.

To determine the truthfulness of the statements about the relation R on the set A, we need to analyze its properties: reflexivity, symmetry, and transitivity.

Understanding Relations on a Set

A relation R from a set A to a set B is a subset of the Cartesian product $A \times B$. In this question, the relation R is defined on the set A = {l, m, n}, which means R is a subset of $A \times A$. The given relation R is the empty set, denoted as $R = \emptyset = \{\}$.

Analyzing Reflexivity of Relation R

A relation R on a set A is said to be reflexive if for every element $x \in A$, the ordered pair $(x, x)$ belongs to R.

  • The given set is $A = \{l, m, n\}$.
  • For R to be reflexive, it must contain the pairs $(l, l)$, $(m, m)$, and $(n, n)$.
  • However, the relation R is given as the empty set, $R = \{\}$.
  • Since none of the pairs $(l, l)$, $(m, m)$, or $(n, n)$ are present in R, the relation R is not reflexive.

Analyzing Symmetry of Relation R

A relation R on a set A is said to be symmetric if for all elements $x, y \in A$, whenever $(x, y)$ belongs to R, then $(y, x)$ must also belong to R.

  • The given relation is $R = \{\}$.
  • To check for symmetry, we look for pairs $(x, y)$ in R.
  • Since R is the empty set, there are no pairs $(x, y)$ present in R.
  • The condition for symmetry is an "if-then" statement. When the "if" part (the premise) is false (i.e., there are no pairs $(x, y)$ in R), the entire "if-then" statement is considered true, regardless of the "then" part. This concept is known as vacuously true.
  • Therefore, because there are no elements $(x, y) \in R$ for which the symmetric condition could fail, the relation R is symmetric.

Analyzing Transitivity of Relation R

A relation R on a set A is said to be transitive if for all elements $x, y, z \in A$, whenever $(x, y)$ belongs to R and $(y, z)$ belongs to R, then $(x, z)$ must also belong to R.

  • The given relation is $R = \{\}$.
  • To check for transitivity, we look for pairs $(x, y) \in R$ and $(y, z) \in R$.
  • Since R is the empty set, there are no such pairs $(x, y)$ and $(y, z)$ present in R.
  • Similar to symmetry, the condition for transitivity is an "if-then" statement. The "if" part (the premise: $(x, y) \in R$ AND $(y, z) \in R$) is false because R is empty.
  • Thus, the entire "if-then" statement is vacuously true.
  • Therefore, the relation R is transitive.

Summarizing Properties of Relation R

Let's summarize the findings for the relation R = {} on the set A = {l, m, n}:

Property Condition Result for R = {}
Reflexive For all $x \in A$, $(x, x) \in R$ Not satisfied (e.g., $(l, l) \notin R$)
Symmetric For all $x, y \in A$, if $(x, y) \in R$, then $(y, x) \in R$ Vacuously true (no $(x, y) \in R$)
Transitive For all $x, y, z \in A$, if $(x, y) \in R$ and $(y, z) \in R$, then $(x, z) \in R$ Vacuously true (no $(x, y)$ and $(y, z)$ pairs in R)

Based on this analysis, R is not reflexive, is symmetric, and is transitive.

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Important Questions from Types of Relations

  1. Let X be the set of all persons living in a city. Persons x, y in X are said to be related as x < y if y at least 5 years older than x. which one of the following is correct?

  2. Let Z be the set of integers and aRb, where a, b ∈ Z if and only if (a - b) is divisible by 5.

    Consider the following statements:

    1. The relation R partitions Z into five equivalent classes

    2. Any two equivalent classes are either equal or disjoint

    Which of the above statements is/are correct?

  3. Suppose there is a relation * between the positive x and y given x * y if the only if x ≤ y 2. Then which one of the following is correct?

  4. The relation R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3), (1, 3)} on a set A = {1, 2, 3} is

  5. The maximum number of equivalence relations on the set A = {1, 2, 3, 4} are

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