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Question

Let A be a nonsingular diagonalizable matrix of order 3 with eigenvalues λ1, λ2, λ3. Then A-1 is diagonalizable if:

The correct answer is

λ1 = 2, λ2 = 1, λ3 = 3

The inverse of every nonsingular diagonalizable matrix is diagonalizable. Only the listed triple (2,1,3) has no zero eigenvalue and is consistent with nonsingularity. The other triples make the matrix singular.

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Important Questions from Determinants

  1. An $n \times n$ square matrix $A$ satisfies $A^T = A^{-1}$. The determinant of this matrix may take which of the following value(s)?
  2. The determinant of the matrix $\begin{pmatrix} 1 & p & q + r \\ 1 & q & r + p \\ 1 & r & p + q \end{pmatrix}$ is ______.

  3. Let $f(x) = \begin{vmatrix} x^3 & \sin x & \cos x \\ 6 & -1 & 0 \\ p & p^2 & p^3 \end{vmatrix}$ 

    where $p$ is a constant. 

    The value of $\frac{d^3}{dx^3}f(x)$ at $x = 0$ is

  4. How many matrices of different orders are possible with elements comprising all prime numbers less than 30?

  5. If A is a square matrix of order 3 and det A = 5, then what is det [(2A) -1 ] equal to ?

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