Match List-I with List-IIList-1 List-II (A) $A^T = A$ (I) A is a singular matrix (B) $A^T = -A$ (II) A is a non-singular matrix (C) $|A| = 0$ (III) A is a skew symmetric matric (D) $|A| \neq 0$ (IV) A is a symmetric matric
Choose the correct answer from the options given below:
This question tests the understanding of fundamental matrix properties related to the transpose of a matrix ($A^T$) and its determinant ($|A|$).
We need to match the conditions given in List-I with their corresponding definitions or properties in List-II.
Based on the matching derived above, the correct pairings are:
This set of matches corresponds to Option 2.
The eigenvalues of the 3 × 3 matrix M = \(\left(\begin{array}{lll}\rm a^2 & \rm a b & \rm a c \\ \rm a b & \rm b^2 & \rm b c \\ \rm a c & \rm b c &\rm c^2\end{array}\right)\) are
A generic 3 × 3 real matrix A has eigenvalues 0, 1 and 6, and I is the 3 × 3 identity matrix. The quantity/quantities that cannot be determined from this information is/are the
If \(A = \(\left[ {\begin{array}{} {coshx}&{sinhx}\\ { - sinhx}&{coshx} \end{array}} \right])\) , then trace (A 2) is equal to
Let A be a non-singular diagonalisable matrix of order 3 with eignvalues λ1, λ2, λ3. A -1 is diagonalisable if:
Assertion(A): If A is any Matrix given by A = \(\left(\begin{array}{ccc}5 & 0 & 3 \\ −1 & 0 & 2 \\ 1 & 0 & 1\end{array}\right)\)
Then det A = 0, since all elements in column II are zero
Reason (R): Laplace expansion permits evaluation of a determinant along any row or column