Length of three sides of a triangular field are 15m, 19m, and 22m respectively. What is the area of the field? (correct to one decimal place)
140.2 m²
The problem asks us to find the area of a triangular field when the lengths of its three sides are given. The side lengths are 15m, 19m, and 22m. To find the area of a triangle when all three sides are known, we can use Heron's formula.
Heron's formula is a useful tool for calculating the area of a triangle when only the lengths of the three sides are provided. The formula is given by:
\( A = \sqrt{s(s-a)(s-b)(s-c)} \)
Where:
The semi-perimeter \( s \) is half the perimeter of the triangle. It is calculated as:
\( s = \frac{a+b+c}{2} \)
Let the side lengths of the triangular field be \( a = 15 \) m, \( b = 19 \) m, and \( c = 22 \) m.
First, we find the semi-perimeter \( s \):
\( s = \frac{15 + 19 + 22}{2} = \frac{56}{2} = 28 \) m
Next, we calculate the differences between the semi-perimeter and each side length:
Now, we substitute these values into Heron's formula:
\( A = \sqrt{s(s-a)(s-b)(s-c)} \)
\( A = \sqrt{28 \times 13 \times 9 \times 6} \)
Let's calculate the product inside the square root:
\( 28 \times 13 = 364 \)
\( 9 \times 6 = 54 \)
\( A = \sqrt{364 \times 54} \)
\( 364 \times 54 = 19656 \)
\( A = \sqrt{19656} \)
Calculating the square root of 19656:
\( \sqrt{19656} \approx 140.199857... \)
The question asks for the area to be corrected to one decimal place. Rounding 140.199857... to one decimal place gives 140.2 m².
Thus, the area of the triangular field is approximately 140.2 m².
| Parameter | Value | Calculation/Note |
|---|---|---|
| Side a | 15 m | Given side length |
| Side b | 19 m | Given side length |
| Side c | 22 m | Given side length |
| Semi-perimeter (s) | 28 m | \( s = (a+b+c)/2 \) |
| (s-a) | 13 m | \( 28 - 15 \) |
| (s-b) | 9 m | \( 28 - 19 \) |
| (s-c) | 6 m | \( 28 - 22 \) |
| Area (\( A \)) | \( \sqrt{19656} \) m² | \( A = \sqrt{s(s-a)(s-b)(s-c)} \) |
| Area (rounded) | 140.2 m² | Rounded to one decimal place |
There are several ways to calculate the area of a triangle, depending on the information available:
Heron's formula is powerful because it only requires side lengths, which are often simpler to measure in real-world scenarios like surveying a field.
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