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Question

Length of three sides of a triangular field are 15m, 19m, and 22m respectively. What is the area of the field? (correct to one decimal place)

The correct answer is

140.2 m²

Finding the Area of a Triangular Field

The problem asks us to find the area of a triangular field when the lengths of its three sides are given. The side lengths are 15m, 19m, and 22m. To find the area of a triangle when all three sides are known, we can use Heron's formula.

Understanding Heron's Formula

Heron's formula is a useful tool for calculating the area of a triangle when only the lengths of the three sides are provided. The formula is given by:

\( A = \sqrt{s(s-a)(s-b)(s-c)} \)

Where:

  • \( A \) is the area of the triangle.
  • \( a, b, \) and \( c \) are the lengths of the three sides of the triangle.
  • \( s \) is the semi-perimeter of the triangle.

The semi-perimeter \( s \) is half the perimeter of the triangle. It is calculated as:

\( s = \frac{a+b+c}{2} \)

Step-by-Step Calculation

Let the side lengths of the triangular field be \( a = 15 \) m, \( b = 19 \) m, and \( c = 22 \) m.

Step 1: Calculate the Semi-Perimeter (s)

First, we find the semi-perimeter \( s \):

\( s = \frac{15 + 19 + 22}{2} = \frac{56}{2} = 28 \) m

Step 2: Calculate the Terms (s-a), (s-b), and (s-c)

Next, we calculate the differences between the semi-perimeter and each side length:

  • \( s - a = 28 - 15 = 13 \) m
  • \( s - b = 28 - 19 = 9 \) m
  • \( s - c = 28 - 22 = 6 \) m

Step 3: Apply Heron's Formula

Now, we substitute these values into Heron's formula:

\( A = \sqrt{s(s-a)(s-b)(s-c)} \)

\( A = \sqrt{28 \times 13 \times 9 \times 6} \)

Let's calculate the product inside the square root:

\( 28 \times 13 = 364 \)

\( 9 \times 6 = 54 \)

\( A = \sqrt{364 \times 54} \)

\( 364 \times 54 = 19656 \)

\( A = \sqrt{19656} \)

Step 4: Calculate the Square Root and Round

Calculating the square root of 19656:

\( \sqrt{19656} \approx 140.199857... \)

The question asks for the area to be corrected to one decimal place. Rounding 140.199857... to one decimal place gives 140.2 m².

Thus, the area of the triangular field is approximately 140.2 m².

Revision Table: Triangular Field Area Calculation

Parameter Value Calculation/Note
Side a 15 m Given side length
Side b 19 m Given side length
Side c 22 m Given side length
Semi-perimeter (s) 28 m \( s = (a+b+c)/2 \)
(s-a) 13 m \( 28 - 15 \)
(s-b) 9 m \( 28 - 19 \)
(s-c) 6 m \( 28 - 22 \)
Area (\( A \)) \( \sqrt{19656} \) m² \( A = \sqrt{s(s-a)(s-b)(s-c)} \)
Area (rounded) 140.2 m² Rounded to one decimal place

Additional Information: Area of Triangles

There are several ways to calculate the area of a triangle, depending on the information available:

  • Base and Height: If the base (b) and corresponding height (h) are known, the area is \( A = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} bh \). This is the most common formula.
  • Two Sides and Included Angle: If two sides (a, b) and the angle (\( \gamma \)) between them are known, the area is \( A = \frac{1}{2} ab \sin(\gamma) \). Similarly for other pairs of sides and their included angles.
  • Three Sides (Heron's Formula): As used in this problem, if all three sides (a, b, c) are known, the area can be calculated using Heron's formula: \( A = \sqrt{s(s-a)(s-b)(s-c)} \), where \( s = (a+b+c)/2 \). This formula is particularly useful when the height is not easily determined.

Heron's formula is powerful because it only requires side lengths, which are often simpler to measure in real-world scenarios like surveying a field.

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Important Questions from Geometry

  1. The angles of a cyclic quadrilateral, taken in order, are x°, (3x - 30)°, (y + 30)°, and (2x - y)°. Find the measure of the smallest angle of the quadrilateral.

  2. If 2cosθ = √3, then what is the value of tan 2θ?

  3. A triangle with vertices (3,1), (-1,0), (2,5) is:

  4. If cos (x−y) = √3/2 and sin (x + y) = 1, where x > y, then the value of y is:

  5. The area (in sq units) of the triangle by joining the points (3,0), (0,6) and (-5,0) is

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