This problem involves calculating the final length of a stem experiencing arithmetic growth. Arithmetic growth means the length increases by a constant amount over a specific period.
The formula for arithmetic growth is:
$L_t = L_0 + (r \times t)$
Where:
We are given the following values:
First, calculate the total growth over the 7 days:
$ \text{Total Growth} = r \times t $
$ \text{Total Growth} = 30\text{ cm/day} \times 7\text{ days} = 210\text{ cm} $
Next, add the total growth to the initial length to find the final length:
$ L_7 = L_0 + \text{Total Growth} $
$ L_7 = 20\text{ cm} + 210\text{ cm} = 230\text{ cm} $
The length of the stem at the end of the $7^{\text{th}}$ day is $230\text{ cm}$.
| List I (Growth Regulator) | List II (Function/Effect) |
| A. 2,4-D | I. Brewing industry |
| B. $GA_3$ | II. Stimulation of stomatal closure |
| C. Kinetin | III. Herbicide |
| D. ABA | IV. Nutrient mobilisation |
| List I (Process) | List II (Location) |
| A. Glycolysis | I. Inner mitochondrial membrane |
| B. ETS | II. Mitochondrial matrix |
| C. Accumulation of protons | III. Cytoplasm |
| D. Krebs' cycle | IV. Intermembrane space |
| List I (Growth Regulator) | List II (Function/Effect) |
| A. 2,4-D | I. Brewing industry |
| B. $GA_3$ | II. Stimulation of stomatal closure |
| C. Kinetin | III. Herbicide |
| D. ABA | IV. Nutrient mobilisation |