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Question

LEDs fabricated from GaAsP emit radiations in the

The correct answer is

visible region

GaAsP LEDs Emission Region

Light Emitting Diodes (LEDs) are essential semiconductor devices that convert electrical energy directly into light. The specific color or wavelength of the light emitted by an LED is determined by the bandgap energy of the semiconductor material used in its construction.

Semiconductor LED Operation

An LED operates on the principle of electroluminescence. When a positive voltage (forward bias) is applied across the p-n junction of the semiconductor material, electrons from the n-type region and holes from the p-type region are injected into the depletion region and recombine. This recombination process releases energy, which is emitted in the form of photons (light). The energy of these emitted photons corresponds to the bandgap energy (\(E_g\)) of the semiconductor material.

The relationship between the bandgap energy and the wavelength (\(\lambda\)) of the emitted light is given by the formula:

\[E_g = \frac{hc}{\lambda}\]

Where:

  • \(h\) is Planck's constant (approximately \(6.626 \times 10^{-34}\) J·s)
  • \(c\) is the speed of light in vacuum (approximately \(3 \times 10^8\) m/s)
  • \(\lambda\) is the wavelength of the emitted photon

For practical calculations, if \(E_g\) is expressed in electron volts (eV) and \(\lambda\) in nanometers (nm), the formula can be approximated as:

\[E_g \approx \frac{1240}{\lambda}\]

GaAsP Semiconductor Properties

Gallium Arsenide Phosphide (GaAsP) is a compound semiconductor material widely utilized in the fabrication of optoelectronic devices, including LEDs. It is a ternary alloy, meaning its composition can be varied by changing the ratio of arsenic (As) to phosphorus (P). This unique property allows for precise tuning of the material's bandgap energy.

By adjusting the proportion of phosphorus in the GaAsP alloy (e.g., \(GaAs_{1-x}P_x\)), engineers can control the bandgap energy. A higher phosphorus content generally leads to a larger bandgap energy, while a lower phosphorus content results in a smaller bandgap energy. This tunability is crucial for producing LEDs that emit light at specific wavelengths and, consequently, specific colors.

GaAsP Visible Light Emission

The human eye can perceive light within the visible spectrum, which typically spans wavelengths from approximately 380 nanometers (nm) to 750 nm. This range corresponds to photon energies roughly between 1.65 eV (for red light) and 3.26 eV (for violet light).

GaAsP is an ideal material for LEDs because its direct bandgap can be engineered to fall within this visible light energy range. Depending on the exact composition:

  • LEDs made with GaAsP containing a higher percentage of phosphorus (e.g., \(GaAs_{0.35}P_{0.65}\)) typically emit shorter wavelengths, such as yellow or orange light.
  • LEDs with a lower percentage of phosphorus (e.g., \(GaAs_{0.6}P_{0.4}\)) emit longer wavelengths, commonly red light.

Due to this bandgap engineering capability, GaAsP is a common material for manufacturing red, orange, and yellow LEDs, which are all part of the visible spectrum. The material's efficiency in emitting light directly from electron-hole recombination makes it suitable for these applications.

Conclusion on GaAsP LED Radiation

Based on its tunable direct bandgap characteristics, Gallium Arsenide Phosphide (GaAsP) is specifically chosen for fabricating LEDs that emit light within the visible region of the electromagnetic spectrum. This makes GaAsP LEDs suitable for various applications requiring visible light, such as indicator lights, signage, and display technologies.

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Important Questions from LED

  1. As the colour varies, forward voltage varies, in:

  2. What is the typical range of the forward voltage of an LED?

  3. An LED has lower output power, ________ switching speed and _______ spectral width than the LASER as an optical source.

  4. What does LED stand for?

  5. The value of current limiting resistor for a stack of 4 LED's connected in series will be ______ if the LED's are 3 V, 3 mA and DC source is 15 V.

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