It takes 15 minutes to fill an oil tank. However the oil tank is being emptied through an exhaust pipe, which can empty it in 30 minutes. If this exhaust pipe remains open, how long will it take to fill this tank completely? A. 20 minutes B. 25 minutes C. 30 minutes D. 40 minutes
C
This question asks us to figure out how long it takes to fill an oil tank when there's a pipe filling it and an exhaust pipe simultaneously emptying it. This is a classic example of a 'pipes and cisterns' problem, which deals with rates of work.
First, we need to determine the rate at which the tank is filled by the filling pipe and the rate at which it is emptied by the exhaust pipe. The rate is usually expressed as the fraction of the tank filled or emptied per unit of time (in this case, per minute).
When both pipes are operating at the same time, one is filling and the other is emptying. The net change in the amount of oil in the tank per minute is the difference between the filling rate and the emptying rate. Since the filling pipe is working against the emptying pipe, we subtract the emptying rate from the filling rate to find the net filling rate.
Net filling rate = Rate of filling - Rate of emptying
Net filling rate = \( \frac{1}{15} - \frac{1}{30} \)
To subtract these fractions, we need a common denominator, which is 30.
\( \frac{1}{15} = \frac{1 \times 2}{15 \times 2} = \frac{2}{30} \)
So, the net filling rate is:
Net filling rate = \( \frac{2}{30} - \frac{1}{30} = \frac{2 - 1}{30} = \frac{1}{30} \)
This means that with both pipes open, \( \frac{1}{30} \) of the tank is filled every minute.
The net filling rate is \( \frac{1}{30} \) of the tank per minute. This means it takes 30 minutes to fill 1 whole tank. We can calculate the total time by taking the reciprocal of the net filling rate.
Time taken to fill the tank = \( \frac{1}{\text{Net filling rate}} \)
Time taken = \( \frac{1}{\frac{1}{30}} = 1 \times 30 = 30 \) minutes
Therefore, it will take 30 minutes to fill the oil tank completely when the exhaust pipe remains open.
| Activity | Time Taken | Rate (per minute) |
|---|---|---|
| Filling | 15 minutes | \( \frac{1}{15} \) |
| Emptying | 30 minutes | \( -\frac{1}{30} \) (negative indicates emptying) |
| Net effect (Filling + Emptying) | Calculated below | \( \frac{1}{15} - \frac{1}{30} = \frac{1}{30} \) |
Since the net rate is \( \frac{1}{30} \) tank per minute, the time to fill 1 tank is \( \frac{1}{1/30} = 30 \) minutes.
When the oil tank is being filled by a pipe that takes 15 minutes and simultaneously emptied by an exhaust pipe that takes 30 minutes, the net rate of filling is slower. The effective rate is the difference between the filling rate and the emptying rate. The calculation shows the net rate is \( \frac{1}{30} \) of the tank per minute, meaning it takes 30 minutes to fill the entire tank.
| Concept | Explanation | Formula/Idea |
|---|---|---|
| Rate of Work | The amount of work done (fraction of tank filled/emptied) per unit of time. | Rate = \( \frac{1}{\text{Time Taken}} \) |
| Pipes Filling Together | If pipes A and B fill a tank in \( t_A \) and \( t_B \) respectively, their combined rate is the sum of individual rates. | Combined Rate = \( \frac{1}{t_A} + \frac{1}{t_B} \) |
| Pipe Filling, Pipe Emptying | If pipe A fills in \( t_A \) and pipe B empties in \( t_B \), the net rate when both are open is the filling rate minus the emptying rate. | Net Rate = \( \frac{1}{t_A} - \frac{1}{t_B} \) |
| Time to Complete Work | The total time taken to complete the whole work (fill 1 tank) is the reciprocal of the net rate of work. | Time = \( \frac{1}{\text{Net Rate}} \) |
Pipe and cistern problems are commonly encountered in aptitude tests and represent applications of work and time concepts. Key things to remember:
Understanding how to calculate rates and combine them is crucial for solving these types of problems efficiently.
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